Given: 3y cos x = x² + y²
Define

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
y' [3 cos(x) - 2y] = 2x + 3y sinx)
Answer:
Answer:
Question Number 2 is 20
Question number 3 is 18x-32
Step-by-step explanation:
Answer:
(x + y - 2xy)*(x + y + 2xy)
Step-by-step explanation:
x^2-4x^2y^2+y^2+2*x*y
=x^2 + 2xy + y^2 - (2xy)^2
=(x + y)^2 - (2xy)^2
=(x + y - 2xy)*(x + y + 2xy)