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Ulleksa [173]
4 years ago
15

how does the area of a circle change if the if the radius is multiplied by factor of n where n is a whole number?

Mathematics
1 answer:
Alex777 [14]4 years ago
6 0
Radius is half that of the diameter and area =pi times radius squared then the area wouldn't be decimal format if it was while number I have no idea without looking at my notes... Coffee here I come
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Put (4 x 10)+ (5x 12)=100 into a word problem
Alexxandr [17]

Answer:

what is 40 plus 60

Step-by-step explanation:

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3 years ago
How do I solve this? can someone please help? thank you! y=3x+4 y=x-2 ​
Alecsey [184]

Answer:

Step-by-step explanation:

y = 3x+4 and y = x-2

3x+4 = x-2

2x+4 = -2

2x = -6

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3 years ago
Can I have help on 38 please?
Jobisdone [24]
D2 - d + 4d = d2 - 8d
d2 + 3d = d2 - 8d
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6 0
4 years ago
In a study of the effect of cooling rate on the hardness of welded joints, 50 welds cooled at a rate of 10°C/s had an average Ro
Studentka2010 [4]

Answer:

a) The 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

b) No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =91.1 represent the sample mean 1

\bar X_2 =90.7 represent the sample mean 2

n1=50 represent the sample 1 size  

n2=40 represent the sample 2 size  

s_1 =6.55 sample standard deviation for sample 1

s_2 =4.32 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Part a

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =91.1-90.7=0.4

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n_1 +n_2 -1=50+40-2=88  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,88)".And we see that t_{\alpha/2}=1.987  

The standard error is given by the following formula:

SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=1.325

Now we have everything in order to replace into formula (1):  

0.4-1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=-1.887  

0.4+1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=2.687  

So on this case the 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

Part b

No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

3 0
3 years ago
Solve the equation for x: 6-(4x-2)/5=x
Mila [183]
Probably 3 5/9 around that I’m pretty sure
3 0
3 years ago
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