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Scorpion4ik [409]

2 years ago

5

What is the weight (in grams) of a liquid that exactly fills a 202 milliliter container if the density of the liquid is 0.685gra

ms over milliliter? round to the nearest hundredth when necessary, and only enter numerical values, which can include a decimal point.

1 answer:

Citrus2011 [14]2 years ago

6 0

Answer:

138.37 g

Step-by-step explanation:

Mass is the product of density and volume.

<h3>Mass</h3>

M = ρV = (0.685 g/mL)(202 mL) = 138.37 g

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If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f

levacccp [35]

Answer:

Part A) Annual $\$66,480.95$

Part B) Semiannual $\$66,862.38$

Part C) Monthly $\$67,195.44$

Part D) Daily $\$67,261.54$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part A)

<u><em>Annual</em></u>

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=1$

substitute in the formula above

$A=47,400(1+\frac{0.07}{1})^{1*5}$

$A=47,400(1.07)^{5}$

$A=\$66,480.95$

Part B)

<em><u>Semiannual</u></em>

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=2$

substitute in the formula above

$A=47,400(1+\frac{0.07}{2})^{2*5}$

$A=47,400(1.035)^{10}$

$A=\$66,862.38$

Part C)

<em><u>Monthly</u></em>

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=12$

substitute in the formula above

$A=47,400(1+\frac{0.07}{12})^{12*5}$

$A=47,400(1.0058)^{60}$

$A=\$67,195.44$

Part D)

<em><u>Daily</u></em>

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=365$

substitute in the formula above

$A=47,400(1+\frac{0.07}{365})^{365*5}$

$A=47,400(1.0002)^{1,825}$

$A=\$67,261.54$

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Answer:

y=6x-5

Step-by-step explanation:

1) Use slope formula to find the slope. Slope is 6

1a) Substitute (1,1) in the equation. -5

1b) y=6x-5

<u>Hope this helps :-)</u>

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