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Vadim26 [7]
3 years ago
11

A factor other than the independent variable that might produce an effect in an experiment is called a

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0
The answer is Confounding Variable
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PLEASEE HELP ANYONE
Diano4ka-milaya [45]
There are two blue marbles so you have a 2/8 probability of drawing a blue marble on each draw since the marble is replaced after the first draw. 2/8 can be simplified to be 1/4 and then converted to be 0.25 per draw. 0.25 plus 0.25 equals 0.5. Since we are dealing with percentages multiply 0.5 x 100 which equals 50. Now take 50 and divided by the total number of marbles in the bag which is 8. 50 divided by 8 equals 6.25. So it would be about 6%.
8 0
3 years ago
What is the quotient of 65,610 ÷ 18?
ankoles [38]
The answer to this is 3645
5 0
3 years ago
Read 2 more answers
Lines k and n intersect on the y-axis
avanturin [10]

a) The equation of line k is:

y = -\frac{202}{167}x + \frac{598}{167}

b) The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

The equation of a line, in <u>slope-intercept formula</u>, is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the value of y when x = 0.

Item a:

  • Line k intersects line m with an angle of 109º, thus:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

In which m_1 and m_2 are the slopes of <u>k and m.</u>

  • Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}

  • The tangent of 109 degrees is \tan{109^{\circ}} = -\frac{29}{10}
  • Thus, the slope of line m is found solving the following equation:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}

m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2

m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}

\frac{167m_2}{80} = \frac{-202}{80}

m_2 = -\frac{202}{167}

Thus:

y = -\frac{202}{167}x + b

It goes through point (-2,6), that is, when x = -2, y = 6, and this is used to find b.

y = -\frac{202}{167}x + b

6 = -\frac{202}{167}(-2) + b

b = 6 - \frac{404}{167}

b = \frac{6(167)-404}{167}

b = \frac{598}{167}

Thus. the equation of line k, in slope-intercept formula, is:

y = -\frac{202}{167}x + \frac{598}{167}

Item b:

  • Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

-\frac{202}{167}m = -1

m = \frac{167}{202}

Then

y = \frac{167}{202}x + b

Also goes through point (-2,6), thus:

6 = \frac{167}{202}(-2) + b

b = \frac{(2)167 + 202(6)}{202}

b = \frac{1546}{202}

The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

A similar problem is given at brainly.com/question/16302622

7 0
2 years ago
A. Write an expression to represent the difference between the two points shown on the number line.
Maru [420]
-1.6 - 0.3 
I hope this hepled you and that the answer is correct

8 0
3 years ago
Read 2 more answers
Solve the equation identify extraneous solutions
PIT_PIT [208]

Answer:

Step-by-step explanation:

The goal to solving any equation is to have x = {something}.  That means we need to get the x out from underneath that radical.  It's a square root, so we can "undo" it by squaring.  Square both sides because this is an equation.  Squaring both sides gives you

x^2=-3x+40

Get everything on one side of the equals sign and set the quadratic equal to 0:

x^2+3x-40=0

Throw this into the quadratic formula to get that the solutions are x = 5 and -8.  We need to see if only one works, both work, or neither work in the original equation.

Does 5=\sqrt{-3(5)+40}?

5=\sqrt{-15+40} and

5=\sqrt{25}

and 5 = 5.  So 5 works.  Let's try -8 now:

-8=\sqrt{-3(-8)+40} and

-8=\sqrt{24+40} so

-8=\sqrt{64}

-8 = 8?  No it doesn't.  So only 5 works. Your choice is the third one down.

6 0
3 years ago
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