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qwelly [4]
3 years ago
5

Selected t-account balances for bloomfield company are shown below as of january 31, which reflect its accounting adjustments. t

he firm uses a calendar-year accounting period, but prepares monthly accounting adjustments. if the amount in supplies expense represents the january 31 adjustment for the supplies used in january, and $620 worth of supplies were purchased during january, what was the january 1 beginning balance of supplies?
Business
1 answer:
sukhopar [10]3 years ago
3 0

Answer:

The question is incomplete;The following additional information completes the question;

Supplies 31 January        $1,800

Supplies Expense 31 January $1,920          

Explanation:

The opening Balance of Supplies as at January 1 was;

Supplies-Closing                        $1,800

Supplies Purchased                    ($620)

Supplies Expense out                 $1,920  

Supplies Opening January 1        $3,100

The T account is prepared in columnar form. The opening supplies balance at January 1 was $3,100

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a retailer has been selling 2800 tablet computers a week at $250 each. the marketing department estimates that an additional 80
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From the given information, The demand function is (P) = -x/8 + 600. The demand function illustrates the causal connection between the quantity of a commodity that is demanded and its numerous determinants.

The demand function is given by P - P1 = m(x-x1)

Since, m = -10/80    (i.e. additional 80 tablets every $10)

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A woman worked for 30 years before retiring. At the end of the first year of employment she deposited 5000 into an account for h
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$797,837

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the first withdrawal is $50,000

the second is $51,500

and so on...

the formula that used to solve the interest rate earned by the annuity is:

$50,000 x {[(1 + i)³⁰ - (1 + 3%)³⁰] / [(1 + i)³⁰ x (i - 3%)]} x (1 + i) = $5,000 x {[(1 + i)³⁰ - (1 + 3%)³⁰] / (i - 3%)}

we start to simplify the equation by cancelling  {[(1 + i)³⁰ - (1 + 3%)³⁰] / (i - 3%)}

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now we cancel $5,000 on each side:

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now lets take away (1 + i):

10 / (1 + i)²⁹ = 1

things get a little bit more simple now:

10 = (1 + i)²⁹

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now we replace i in any equation:

= $50,000 x {[(1 + 0.082636734)³⁰ - 1.03³⁰] / [(1 + 0.082636734)³⁰ x (0.082636734 - 0.03)]} x (1 + 0.082636734)

= $50,000 x  {[10.82636738 - 2.427262471] / [10.82636738 x 0.052636734]} x (1 + 0.082636734)

= $50,000 x  {8.399104909 / 0.56986462} x (1.082636734)

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