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4 years ago

T^3: (x,y) —> Options are in the picture

Mathematics

1 answer:

12345 [234]4 years ago

6 0

I think there is a rule based in there, so Like:

T^1 : (x , y) ------> (x+3 , y+1)

T^2: (x, y ) -------> (x +3 +3 , y+1+1) = (x+6, y+2)

So I think T^3 should be:

T^3: (x, y) -------> ( x+3+3+3 , y+1+1+1) = (x+9, y+3)

So the answer should be the 2nd.

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The difference of 3 times a number and 15 is no less than the square of the number.

jok3333 [9.3K]

Answer:

(B) The inequality that represents this relationship is $3x < x^2 +15$

Step-by-step explanation:

Let us assume the given number = x

⇒ 3 times the given number = 3 (x) = 3x

Square of the given number = $(x)^2 = x^2$

Now, According to the question:

The difference of (3 x) and 15 is no less than $x^2$

⇒ $3x - 15 < x^2\\ \implies 3x < x^2 +15$

or, $3x < x^2 +15$

Hence, the given inequality is represented as $3x < x^2 +15$

8 0

3 years ago

Read 2 more answers

Use a calculator to find a decimal approximation for the following trigonometric function sin 28°48

Bumek [7]

The decimal approximation for the trigonometric function sin 28°48' is

Given the trigonometric function is sin 28°48'

The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.

To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°

sin (28°48') = sin(28° ₊ (48 × 1/60)°)

= sin(28° ₊ (48 /60)°)

= sin(28° ₊ 4°/5)

= sin(28° ₊ 0.8°)

= sin(28.8°)

= 0.481753

Therefore sin (28°48') is 0.481753.

Learn more about Trigonometric functions here:

brainly.com/question/25618616

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5 0

2 years ago

10. When a rubber ball is dropped from a height, h cm on to a flat concrete floor, it rebounds to 3 5 h cm a height of Given a r

Xelga [282]

Step-by-step explanation:

Let the height above which the ball is released be H

This problem can be tackled using geometric progression.

The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is

To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H

a=2H..........r=3/4

However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H

Therefore the total distance travel up to the Nth bounce is

For N=3 one obtains

D=3.625H

7 0

3 years ago

The day's high temperature in St. Louis comma Missouri was recorded as 77 degrees' F. Use the formula Upper C=5/9(F-32) to writ

ludmilkaskok [199]

Answer:

The day's high temperature written as degrees Celsius is 25 degrees' Celsius.

Step-by-step explanation:

The day's high temperature in St. Louis ,Missouri was recorded as 77 degrees F.

We are supposed to find the day's high temperature written as degrees Celsius.

Formula : $C=\frac{5}{9}(F-32)$

Substitute the value of F is 77 degrees

So, $C=\frac{5}{9}(77-32)$

$C=\frac{5}{9}(45)$

C=25

Thus, The day's high temperature written as degrees Celsius is 25 degrees' Celsius.

6 0

3 years ago

The function h ( x ) = 1 x − 1 h ( x ) = 1 x - 1 can be expressed in the form f ( g ( x ) ) f ( g ( x ) ) , where g ( x ) = ( x

Radda [10]

Answer: f(x) = 1^(x + 1)

Step-by-step explanation:

we have that h(x) = 1^x

and h(x) = f(g(x))

This mean that we are evaluating the function f(y) in the point y = g(x)

where g(x) = x - 1

then:

f(g(x) = f(x - 1) = h(x) = 1^x

then we should have that:

f(x) = 1^(x + 1)

then:

f(x - 1) = 1^(x - 1 + 1) = 1^x

4 0

4 years ago