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Leni [432]
4 years ago
9

Write in standard form 12 ten thousands, 8 thousands, 14 hundreds, 7 ones

Mathematics
2 answers:
Readme [11.4K]4 years ago
7 0
129,407
12 ten thousands is 120,000
8 thousand is 8,000
14 hundreds is 1,400
there are no tens
7 ones is 7
so 120,000+8,000+1,400+7=129,407
kipiarov [429]4 years ago
7 0
129,407
hope that helped
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Please help me now plz <br> I will mark you brainliest
cluponka [151]

Answer:

not clear enough to answer your question

3 0
4 years ago
Factor out the coefficient of the variable 5/6s+2/3
DochEvi [55]
Okay. so I'm gonna assume you know what factor out means--were gonna take out 5/6. what we need to know is, how does that affect our ending number 2/3? well, we're gonna have 5/6 times some stuff first off, right?

5/6 ( )

so what's in the parenthesis? well, if we distribute in our mind, S would just have to be by itself for it to work out. so we have

5/6 ( s )

but what about 2/3? well, if we're multiplying everything on the inside by 5/6, how can be get it to cancel and leave 2/3 alone? we could divide 2/3 by 5/6, right?

5/6 ( s + (2/3) / (5/6) )

now, when we distribute our 5/6, we'll have just 2/3 at the end. now let's simplify that end term so it looks a little better. if we divide by a fracion, that's the same as multiplying by the flipped version, so let's do that.

2/3 / 5/6 = 2/3 × 6/5 = 2 (6) / 5 (3) = 12/15

we can reduce 12/15 by dividing the top and bottom by three.

= 4/5

so our final answer would be:

5/6 [S + 4/5] you can redistribute to make sure it matches. Anyway, hope that helps!
6 0
3 years ago
Ile to 12308+11093=??????pomóżcie
BARSIC [14]

Answer:

Twoja odpowiedź brzmi 23401.

Spójrz na zdjęcie, aby uzyskać dalsze wyjaśnienia.

4 0
3 years ago
Please help ASAPPPPPP
g100num [7]

Answer:

Step-by-step explanation:

1/3t+5/12     t=1/4

1/3(1/4)+5/12=1/12

                   =6/12 or if you need it simplified 1/2

3 0
3 years ago
Which of the following has no solution?
tresset_1 [31]

Answer:

(x+11)

Step-by-step explanation:

Solve all options.

1. (x+1

x+1

So,

(x+1

There are solutions.

2. (x+1\le1)\cap (x+1\ge 1)

x+1\le 1\Rightarrow x\le 0\\ \\x+1\ge 1\Rightarrow x\ge 0

So,

(x+1\le 1)\cap (x+1\ge 1)\Rightarrow (x\le 0)\cap (x\ge 0)\Rightarrow (x=0)

There is one solution.

3. (x+11)

x+10

So,

(x+11)\Rightarrow (x0)\Rightarrow (x\in \emptyset)

There are no solutions.

7 0
3 years ago
Read 2 more answers
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