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3 years ago

Factor out the coefficient of the variable 5/6s+2/3

1 answer:

6 0

Okay. so I'm gonna assume you know what factor out means--were gonna take out 5/6. what we need to know is, how does that affect our ending number 2/3? well, we're gonna have 5/6 times some stuff first off, right?

5/6 ( )

so what's in the parenthesis? well, if we distribute in our mind, S would just have to be by itself for it to work out. so we have

5/6 ( s )

but what about 2/3? well, if we're multiplying everything on the inside by 5/6, how can be get it to cancel and leave 2/3 alone? we could divide 2/3 by 5/6, right?

5/6 ( s + (2/3) / (5/6) )

now, when we distribute our 5/6, we'll have just 2/3 at the end. now let's simplify that end term so it looks a little better. if we divide by a fracion, that's the same as multiplying by the flipped version, so let's do that.

2/3 / 5/6 = 2/3 × 6/5 = 2 (6) / 5 (3) = 12/15

we can reduce 12/15 by dividing the top and bottom by three.

= 4/5

so our final answer would be:

5/6 [S + 4/5] you can redistribute to make sure it matches. Anyway, hope that helps!

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Ms. Leverenz is doing an art project with her class. She has a 3 foot piece of ribbon. If she gives each student an eighth of a

vesna_86 [32]

Yes, she will.

<h3>Further explanation</h3>

<u>Given:</u>

Ms. Leverenz is doing an art project with her class.

She has a 3-foot piece of ribbon.
She gives each student an eighth of a foot of ribbon.

<u>Question:</u>

Will she have enough for her class of 22 students?

<u>The Process:</u>

$\boxed{ \ An \ eighth \ is \ \frac{1}{8} \ or \ equal \ to \ \frac{1 \times 125}{8 \times 125} = \frac{125}{1,000} = 0.125 \ }$

Let us draw a diagram that connects between she gives each student an eighth of a foot of ribbon with 22 students in her class.

$\boxed{ \ \frac{1}{8} \ }\boxed{ \ \frac{1}{8} \ }\boxed{ \ \frac{1}{8} \ } \cdot \cdot \cdot \cdot \boxed{ \ \frac{1}{8} \ }\boxed{ \ \frac{1}{8} \ } \\\boxed{1^{st}} \boxed{2^{nd}} \boxed{3^{rd}} \cdot \cdot \cdot \cdot \boxed{21^{st}}\boxed{22^{nd}} \ student$

From the diagram above, let us calculate how long (in ft) the ribbon she has given to 22 students.

$\boxed{ \ \frac{1}{8} \times 22 = ? \ }$

$\boxed{ \ = \frac{22}{8} \ }$

$\boxed{ \ = \frac{16}{8} + \frac{7}{8} \ }$

$\boxed{ \ = 2 + \frac{7}{8} \ }$

$\boxed{\boxed{ \ = 2\frac{7}{8} \ }}$

Therefore, there are $2\frac{7}{8}$ -foot piece of ribbon that she has given.

Ms. Leverenz has a 3-foot piece of ribbon.

$\boxed{ \ 2\frac{7}{8} < 3 \ }$

Thus, because the total number of pieces of ribbon given is smaller than the initial length, she will have enough for her class of 22 students

<h3>Learn more</h3>

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