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3 years ago

Which of the following lists of ordered pairs is a function?

Mathematics

2 answers:

joja [24]3 years ago

7 0

Answer:

Step-by-step explanation:

This list of ordered pair is a function because to be a function, you can not have a repeating x-value. In the other options, they consist of a repeating x-value.

A. Repeating 3

C. Repeating -1

D. Repeating 2

Hence,

the correct option is B.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

arlik [135]3 years ago

5 0

The answer is B
I already did it at school.

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grin007 [14]

Answer:

Step-by-step explanation:

To do this, you need to complete the square.

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Therefore, the correct answer is choice B. Hope this helps!

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4 years ago

Firewood is usually sold by a measure known as a cord. A full cord may be a stack 8*4

densk [106]

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3 years ago

Is 3x squared a factor of 12x squared

Setler79 [48]

Answer:

yes i belive but im not very sure

Step-by-step explanation:

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3 years ago

write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

8 0

2 years ago

30 points!

Oduvanchick [21]

Hey I’m sure it’s 4! Sorry if I’m wrong that’s quite confusing

4 0

3 years ago

Read 2 more answers