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Vilka [71]
2 years ago
7

30 points!

Mathematics
2 answers:
Oduvanchick [21]2 years ago
4 0
Hey I’m sure it’s 4! Sorry if I’m wrong that’s quite confusing
Mrrafil [7]2 years ago
4 0
I don’t see a figure that shows a parallelogram
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Paco orders an ice cream for $1, but realizes his wallet is at home and he only has 3/20 of $1 with him. If his mom pays the rem
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if he has 3/20 of a dollar that calculates to $0.15 and $1.00 minus $0.15 equals $0.85

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HELP PLEASE!!!! Three sides of a triangle are three consecutive positive integers such that the product of the first two is 22 l
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Read 2 more answers
In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
3 years ago
Please solve, due tomorrow!
Darya [45]
5x=25  X= 5
X/3=7  X= 21
2x=14  X= 7
x/2=12 X=6
x/4=6   X=24

4 0
3 years ago
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