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stepan [7]
4 years ago
7

How many pairs of whole numbers have the sum of 110

Mathematics
1 answer:
Alenkasestr [34]4 years ago
8 0
There are 109 pairs. Hoped this helps:)!
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Ok, 2nd time I asked this...
viktelen [127]
<span>Answer:  a) (5x - 1) (x + 6)

Explanation:
</span>5x² + 29x − 6 = (5x - 1) (x + 6)

5x  \    /  -1           -x 
        \/ 
        /\
x    /    \   6            30x
--------------------------------
5x²        -6           29x
-------------------------------
7 0
3 years ago
Help may oplpkpk.........
Diano4ka-milaya [45]

Answer:

A.

Step-by-step explanation:

The answer is A.

Good luck!

5 0
3 years ago
Read 2 more answers
I am stuck on a geometry lesson. It is on the Angle Sum Theorem. It said we have an obtuse trisngle with angles 1, 2, and 3. The
vitfil [10]
The angle sum theorem states that the sum of all the interior angles of a triangle is 180 degrees. In a Euclidean space, the sum of the measure of the interior angles of a triangle sum up to 180 degrees, be it an acute, obtuse, or a right triangle which is the direct result of the angle sum theorem of the triangle
4 0
2 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
Find the equation of the tangent line to the curve y=11xex at the point (0,0). the equation of this tangent line can be written
vichka [17]
y=11xe^x\implies y'=11e^x(x+1)

When x=0, the slope of the tangent line is 11e^0(0+1)=11. The equation of the tangent line in point-slope form is then

y-0=11(x-0)\implies y=11x
5 0
4 years ago
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