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dimaraw [331]
4 years ago
13

Y = 4x + 3 y = 2x − 4 what is the system of equations?

Mathematics
1 answer:
borishaifa [10]4 years ago
4 0

Answer: X=-7/2

               y=-11

Step-by-step explanation:

4x+3=2x-4

4x-2x=-4-3

2x=-7

x=-7/2

y=-7/2*2-4

y=-7-4=-11

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Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
The nth term of a sequence is 2N - six
dolphi86 [110]

Answer:

ok nice to know

Step-by-step explanation:

that wasnt even a ????

4 0
3 years ago
PLEASE HELPPP I WILL MARK BRAINLIEST
Rina8888 [55]

Answer: they are different the difference is 28

Step-by-step explanation:

6 0
3 years ago
What is the value of 6x-3x +7 if x=9?
Lynna [10]

6x - 3x + 7 \\ 3x + 7 \\ 3(9) + 7 \\ 27 + 7 \\  = 34
Combine like terms and "plug in" x into the equation to eventually get 34 after some addition
8 0
3 years ago
(a)
Allisa [31]

Answer:

320,000

Step-by-step explanation:

4 0
3 years ago
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