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4 years ago

Which algebraic expression represents the difference of 54 and s number

Mathematics

2 answers:

ivanzaharov [21]4 years ago

8 0

Answer:

the answer is 54-b

Step-by-step explanation:

took the test

BlackZzzverrR [31]4 years ago

7 0

54 - s

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A triangle has side lengths of 8 8 inches, 12 12 inches, and 16 16 inches. Determine whether this is a right triangle and why. C

arlik [135]

Answer:

It is not a right triangle

Step-by-step explanation:

A triangle has side lengths of 8 inches, 12 inches, and 16 inches.

To determine if it is a Right Triangle, we make use of the Pythagoras Theorem, i.e.

$Hypotenuse^2=Opposite^2+Adjacent^2$

Now the Hypotenuse is always the longest side

$16^{2} =8^2+12^2\\256=64+144\\256=208$

The equality above is not true and in fact

$256\neq 208$

Therefore the 3 numbers do not satisfy Pythagoras theorem and cannot be the lengths of a right triangle.

7 0

3 years ago

Read 2 more answers

Write an equation in standard form for the line that passes through (5, -2) and is perpendicular to 3x-4y=12

Tasya [4]

The equation in standard form for the line that passes through (5, -2) and is perpendicular to 3x - 4y = 12 is 4x + 3y = 14

<h3>Solution:</h3>

Given that line that passes through (5, -2) and is perpendicular to 3x - 4y = 12

We have to find the equation of line

The slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y-intercept

Let us first find the slope of line

Given equation of line is 3x - 4y = 12

On rearranging the above equation to slope intercept form,

3x - 4y = 12

4y = 3x - 12

$y = \frac{3}{4}x - 3$

On comparing the above equation with slope intercept form,

$m = \frac{3}{4}$

Thus the slope of line is $m = \frac{3}{4}$

We know that product of slope of given line and slope of line perpendicular to given line is always -1

slope of given line x slope of line perpendicular to given line = -1

$\begin{array}{l}{\frac{3}{4} \times \text { slope of line perpendicular to given line }=-1} \\\\ {\text {slope of line perpendicular to given line }=\frac{-4}{3}}\end{array}$

Now we have to find the equation of line with slope $m = \frac{-4}{3}$ and passes through (5, -2)

Substitute $m = \frac{-4}{3}$ and (x, y) = (5, -2) in eqn 1

$-2 = \frac{-4}{3}(5) + c\\\\-2 = \frac{-20}{3} + c\\\\-6 = -20 + 3c\\\\3c = 14\\\\c = \frac{14}{3}$

The required equation of line is:

Now substitute $m = \frac{-4}{3}$ and $c = \frac{14}{3}$

$y = \frac{-4}{3}x + \frac{14}{3}$

The standard form of an equation is Ax + By = C

x and y are variables and A, B, and C are integers

Rewriting the above equation,

$y = \frac{-4}{3}x + \frac{14}{3}$

3y = -4x + 14

4x + 3y = 14

Thus the equation of line in standard form is found out

6 0

3 years ago

Use the method of elimination to determine whether the given linear system is consistent or inconsistent. If it is consistent, f

S_A_V [24]

Answer:

Step-by-step explanation:

From the given information;

We will realize that in the 2nd & 3rd equation, the integer "x" is missing.

So, the correct equation should be:

4x - 2 + 6z = 0

x - y - z = 0

2x - y + 3z = 0

By rearrangement; if we switch equation (1) and (2)

x - y - z = 0 ----- (1)

4x - 2 + 6z = 0 ------ (2)

2x - y + 3z = 0 ------ (3)

If we multiply equation (1) and add that to equation (2);

Then, we have:

x - y - z = 0

2y + 10z = 0

2x - y + 3z = 0

Also, if we multiply equation (1) by -2 and add that to equation (3), we have:

x - y - z = 0

2y + 10z = 0

y + 5z = 0

From above recent equation, if we swap equation (2) and (3);

x - y - z = 0

y + 5z = 0

2y + 10z = 0

Then, multiply equation (2) with -2, followed by adding it to equation(3);

Then:

x - y - z = 0

y + 5z = 0

0 = 0

Now, there exists no equation (3). Thus, let assume z = t to solve for x & y

y + 5z = 0

y = -5t

Similarly;

x - y - z = 0

x = -5t + t

x = -4t

Hence;

x = -4t; y = -5t; & z = t

7 0

3 years ago

(5-3i)+(4+2i) what is the solution ?

Vaselesa [24]

Answer:

−14+22i

Step-by-step explanation

yourwelcome

7 0

3 years ago

Read 2 more answers

When the nth root of a is written, it is the positive value that is shown

allsm [11]

The nth root of a is always positive unless, a < 0 and "n" is an odd number. Also if a < 0 and "n" is an even number, then it's an imaginary number. I hope this helps a lot

5 0

3 years ago