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SCORPION-xisa [38]
3 years ago
13

How do I solve this problem

Mathematics
1 answer:
drek231 [11]3 years ago
7 0

Answer:

Car B with a consumption of 1 gallon per 58.2 miles

tho car a has a consumption of 1 gallon per 58.5



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What is 3 and 4/8 + 1 and 1/4​
igomit [66]

x = 3 4/8 + 1 1/4

x = 3 2/4 + 1 1/4

x = 3 1/2 + 1 1/4

x = 3.5 + 1.25

x = 4.75

4.75 = 4 3/4

5 0
3 years ago
Three consecutive integers have a sum of 45. Find the integers.
katrin2010 [14]

Answer:

14,15,16

Step-by-step explanation:

14+15=29

add up 29 + 16 = 45

7 0
3 years ago
An airplane takes off with a full tank of 40,000 gallons of fuel and flies at an average speed of 550 miles per hour. After 8 ho
vivado [14]
The answer is 9,235 because 14,000 - 4,875 is 9,235
8 0
3 years ago
Solve for x. 3x2−10=−5<br><br><br><br> x=±√5/3<br><br> x=±√15/3<br><br> x=±√5/9<br><br> x=±√15/9
Morgarella [4.7K]

HI there i know this is way later than you needed it but I though i would give you the correct answer which is B x=±√15/3 i also have proof from an old test that my answer is right.

8 0
3 years ago
Read 2 more answers
Can’t afford to get wrong please do not write if you don’t know thanks !
Katena32 [7]
You don't need to understand the construction or why it works. You only need to accept the fact that it does. You can figure out the answers to this question by looking at the picture.

RT is tangent to circle Q -- TRUE. That is the point of the construction.

QT is a radius of circle Q -- TRUE. Q is the center and T is on the circle. A line segment from the center to a point on the circle is a radius.

m∠QSR = 90° -- FALSE. Those points lie on the same line. The measure of the angle is 180°.

QS = QT -- FALSE. S lies inside circle Q, so is closer to the center than T, which lies on the circle. (For some choice of point R, S might lie on the circle, but because this statement is not always true, it must be considered false.)

ΔRTQ is a right triangle -- TRUE. A tangent line is always perpendicular to the radius to the point of tangency. The construction succeeds because RTQ is inscribed in semicircle RTQ (centered at S). Such a triangle is always a right triangle.
3 0
4 years ago
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