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slava [35]
3 years ago
7

Stephanie is running a 5K race. She wants to keep track of her time and her distance throughout the race. Identify the independe

nt and dependent variable.
A. The independent variable is the time. The dependent variable is the distance of the race.
B. The independent variable is Stephanie's distance. The dependent variable is the time.
C. The independent variable is the time. The dependent variable is Stephanie's distance.
D. The independent variable is the length of the race. The dependent variable is the time.
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

I think it's D. The independent variable is the length of the race. The dependent variable is the time.

Step-by-step explanation:

Here I'm quoting user kaylaj051903 "because an independent variable is something that is constant and does not change throughout the problem. The dependent variable depends on the independent variable. The race is a 5K race. That will not change. What will change is how long it takes Stephanie to run the 5K race."

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I need help ASAP please
gulaghasi [49]

Answer: x =168

 

Step-by-step explanation:I think it would be 80 plus 88 so its 168.  

4 0
3 years ago
Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=
Nezavi [6.7K]

Given:

The system of equations is

y=2x-5

2y-4x=?

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

y=2x-5

2y-4x=k

Taking all the terms on the left side, the given equations can be rewritten as

-2x+y+5=0

-4x+2y-k=0

The system of equations a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 have infinitely many solutions if

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

We have,

a_1=-2,b_1=1,c_1=5

a_2=-4,b_2=2,c_2=-k

Now,

\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{5}{-k}

On cross multiplication, we get

-k=10

k=-10

Therefore, the missing value is -10.

6 0
3 years ago
A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.
Kobotan [32]

Answer:

The numbers are

-2+3\sqrt{5}   and 3\sqrt{5}

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

so

x=y-2

y=x+2 ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

so

4y+x^2=49 ----> equation B

substitute equation A in equation B

4(x+2)+x^2=49

solve for x

x^2+4x-41=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+4x-41=0

so

a=1\\b=4\\c=-41

substitute in the formula

x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}

x=\frac{-4\pm\sqrt{180}} {2}

x=\frac{-4\pm6\sqrt{5}} {2}

x=-2\pm3\sqrt{5}

so

The positive real number is

x=-2+3\sqrt{5}

Find the value of y

y=x+2

y=-2+3\sqrt{5}+2

y=3\sqrt{5}

6 0
3 years ago
Would be awesome to have help
galben [10]
1331 hope this helped! ;))
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3 years ago
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The answer would be add 13 because
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2 years ago
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