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olya-2409 [2.1K]
3 years ago
5

On your wedding day you leave for the church 30 minutes before the ceremony is scheduled to start. The church is only 10 miles a

way, but you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 15 minutes is only 5 miles per hour. What average speed do you need to go for the rest of the trip to get to the church on time
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

You need to have an average speed of at least 35 miles per hour for the rest of the trip to get to the church on time

Step-by-step explanation:

We use the following relation to solve the question:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

First 15 minutes:

Time of 15 minutes = 0.25 hour, so t = 0.25

Velocity of 5 miles per hour. So the distance is of:

d = vt = 5*0.25 = 1.25

Final 15 minutes:

The will need to drive 10 - 1.25 = 8.75 miles in 15 minutes = 0.25 hours. So, the average speed will need to be of at least:

v = \frac{d}{t} = \frac{8.75}{0.25} = 35

You need to have an average speed of at least 35 miles per hour for the rest of the trip to get to the church on time

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(x - 3)^2 + (y + 1) = 25

Step-by-step explanation:

First find the midpoint of the diameter, because that represents the center of the circle.

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The domain and the range of a function are the set of input and output values, the function can take.

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Answer:

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