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taurus [48]
3 years ago
11

Need help adding these √54 + √24

Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0

Answer:

12.247 Hope I helped

Step-by-step explanation:

\sqrt{54}+\sqrt{24}  \\7.348+4.899\\12.247

SCORPION-xisa [38]3 years ago
3 0

Answer:

5\sqrt[]{6}

Step-by-step explanation:

\sqrt[]{54}+\sqrt[]{24}

We can rewrite 54 as 6*9 and 9 can be rewritten as 3^2.

24 can be rewritten as 3*8 and 8 can be rewritten as 2^3 or 2^2*2

I'm doing this because that way I can easily take those numbers out of the square (2) root.

Let's rewrite our square roots.

\sqrt[]{6*3^2}+\sqrt[]{3*2^2*2}

3 cancels the square in the first square root, and same does 2 squared in the second square root.

3\sqrt[]{6}+2\sqrt[]{3*2}

Solve;

3\sqrt[]{6}+2\sqrt[]{6}

When you have square roots with equal value inside, you can add the numbers outside of it.

3+2(\sqrt[]{6})

5\sqrt[]{6}

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4 0
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Find the solutions to sin2(x) + cos(x) = 1, keeping 0 ≤ x < 2π
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by simplify the eqn.
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3 0
3 years ago
Carson can choose one vehicle (car or truck), one color (blue, red, or silver), and one type of transmission (standard or automa
77julia77 [94]

Answer:

12 possible outcomes

Step-by-step explanation:

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5 0
2 years ago
If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3
horrorfan [7]

Answer:  The correct option is (B) 24 : 25.

Step-by-step explanation:  Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Therefore, the ratio of the area of R to the area of S is

\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0
3 years ago
[im posting this for YALLS benefit- don’t make the same mistake i did besties <33
Anestetic [448]

Answer:

false

Step-by-step explanation:

3 0
3 years ago
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