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taurus [48]
4 years ago
11

Need help adding these √54 + √24

Mathematics
2 answers:
Gennadij [26K]4 years ago
8 0

Answer:

12.247 Hope I helped

Step-by-step explanation:

\sqrt{54}+\sqrt{24}  \\7.348+4.899\\12.247

SCORPION-xisa [38]4 years ago
3 0

Answer:

5\sqrt[]{6}

Step-by-step explanation:

\sqrt[]{54}+\sqrt[]{24}

We can rewrite 54 as 6*9 and 9 can be rewritten as 3^2.

24 can be rewritten as 3*8 and 8 can be rewritten as 2^3 or 2^2*2

I'm doing this because that way I can easily take those numbers out of the square (2) root.

Let's rewrite our square roots.

\sqrt[]{6*3^2}+\sqrt[]{3*2^2*2}

3 cancels the square in the first square root, and same does 2 squared in the second square root.

3\sqrt[]{6}+2\sqrt[]{3*2}

Solve;

3\sqrt[]{6}+2\sqrt[]{6}

When you have square roots with equal value inside, you can add the numbers outside of it.

3+2(\sqrt[]{6})

5\sqrt[]{6}

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2.50 or 2.5

Step-by-step explanation:

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3x – 2y = 17 <br> –2x – 5y = 14 <br> Solve using Elimination Please show work
OleMash [197]

Answer:

The solution is x=3 , y=-4 or (3,-4)

Step-by-step explanation:

Given equations (1 and 2) are:

3x- 2y = 17\\-2x -5y = 14

To solve a system of equation with elimination method, the co-efficients of one of the variables has to be equated and then the equations are added or subtracted to get an equation in one variable.

Multiplying equation 1 by 2:

2(3x-2y) = 2*17\\6x-4y = 34\ \ \ \ \ Eqn\ 3

Multiplying equation 2 by 3

3(-2x-5y) = 3*14\\-6x-15y = 42\ \ \ \ Eqn\ 4

Adding equation 3 and 4

(6x-4y) + (-6x-15y) = 34+42\\6x-4y-6x-15y = 76\\-19y = 76\\\frac{-19y}{-19} = \frac{76}{-19}\\y = -4\\

Putting y = -4 in equation 1

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The solution is x=3 , y=-4 or (3,-4)

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