Answer:
a: z = -1.936
b: 0.0265
d: z < -1.645
Reject H0 if z < -1.645
Step-by-step explanation:
We are given:
H0: µ = 20
HA: µ < 20
n = 60, sample mean: 19.6, σ = 1.6
Since the alternate hypothesis has a < sign in it, it is a left tailed test. The < or > sign in the alternate hypothesis points towards the rejection region.
For a: We need to calculate the test statistic for our situation. This is done with a z-score formula for samples.
For b: we need to use the z-score table to look up the p-value for the score we calculate in part a. The p-value is 0.0265. This means that there is only about a 2.65% chance that the sample values were a result of random chance.
For d: Since the significance level is 0.05, and this is a one tailed test, we have a critical value of z < - 1.645. This means that if the z-score we calculate in part a is less than -1.645, we will reject the null hypothesis
See attached photo for all the calculations!
Answer:
$3.68
Step-by-step explanation:
Answer:
Peter Jonathan Winston (March 18, 1958 – disappeared January 26, 1978) was an American chess player from New York City
Step-by-step explanation:
In late 1977, Winston attended a FIDE-rated tournament at Hunter College High School in New York City. Despite being one of the highest-rated players in the tournament, Winston lost all nine of his games. A few months later, on January 26, 1978, following further surprising game losses, Peter Winston vanished and was never heard from again. According to some sources, Winston's disappearance occurred when he left his home without money, identification, or luggage during a severe winter storm. Many chess players who were close to or acquainted with Winston claim that the champion chess player's mental health had deteriorated, along with his game performance, in the last few years of his life, and that the decline in his mental health may have led to his disappearance.
Answer:
multiply lenght x with
Step-by-step explanation:
