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coldgirl [10]
3 years ago
6

Three salesmen work for the same company, selling the same product. And, although they are all paid on a weekly basis, each sale

sman earns his paycheck differently. Salesman A works strictly on commission. He earns $65 per sale, with a maximum weekly commission of $1,300. Salesman B earns a weekly base salary of $300, plus a commission of $40 per sale. There are no limits on the amount of commission he can earn. Salesman C does not earn any commission. His weekly salary is $900. Suppose Salesmen A and B have the same number of sales and earn the same amount in Week 4 of this month. How many sales must they both have had?
Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

Answer:

12 sales

Hope it helped :3

Rom4ik [11]3 years ago
5 0

Answer:

12 sales

Step-by-step explanation:

Let x represent the number of sales each man had.

For Salesman A, he earns $65 per sale; this is 65x.

For Salesman B, he earns $40 per sale; this is 40x.  We also add to this his weekly salary of $300; this gives us 40x+300.

Since their pay was equal, set the two expressions equal:

65x = 40x+300

Subtract 40x from each side:

65x-40x = 40x+300-40x

25x = 300

Divide both sides by 25:

25x/25 = 300/25

x = 12

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8 0
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Read 2 more answers
First answer gets brainly! 78 points!
aivan3 [116]
1. They both saved 65, causing a 0 dollar difference.

2. 384 ounces

explanation: 4 x 6 = 24
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hope this helps!
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