Answer:
f(x) = x² + 2x + 1
Step-by-step explanation:
you know how to multiply 2 expressions ?
let's say in general we have
(a + b)(c + d)
you take one part of one expression and multiply it with all parts of the other expression, then you take the second part of the first expression and multiply it with all parts of the other expression, then a potential third part, then a fourth part and so on, and you add all these things together (well, depending on the actual signs, of course).
so, we get for this simple generic example
a×c + b×c + a×d + b×d
now we use that understanding for our question here.
(x+1)(x+1) = x×x + 1×x + x×1 + 1×1 = x² + x + x + 1 = x² + 2x + 1

must be continuous in order to be differentiable, so we need to have

By its definition,
, and


so that
.
We want the derivative to exist at
, which requires that we pick an appropriate value for
so that
is also continuous. At the moment, we know
such that

We have


so that
(which means we need to pick
) and so 
90 degrees!
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Using the quadratic formula, plug a=2, b=3, and c=4 into the formula because the equation given can not be factored.
x= -3(+/-) radical (3^2-4*2*2)/2(2)
therefore, x= (-3+ radical 7 i) / 4
x= (-3- radical 7 i )/ 4.
the answer choice is 1.
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