All categories

3 years ago

HELP!

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

Answer:

a) j+c=310; j-c=40
b) (j, c) = (175, 135)
see attached
Jose earned $175; Camden earned $135

Step-by-step explanation:

Let j and c represent Jose's and Camden's earnings, respectively.

(a) One equation can be written for the total; another for the difference:

j + c = 310 . . . . their total earnings

j - c = 40 . . . . . the difference in their earnings

(b) It is convenient to add these two equations to eliminate c:

(j +c) +(j -c) = (310) +(40)

2j = 350

j = 175

Then c can be found as ...

c = j -40 = 175 -40 = 135

The solution is (j, c) = (175, 135).

(c) Using x for j, and y for c, we can use Desmos to graph the equations. The result is attached.

(d) Jose earned $175 over the summer; Camden earned $135.

You might be interested in

100x^2-4=0 quick pls with all work

Finger [1]

4(5x+1)(5x-1) = 0

1. Take out the GCF (in this case, 4)
4(25x^2-1) = 0

2. This can be further factored. Factor the values within the parenthesis
4(5x + 1)(5x -1) = 0

4 0

3 years ago

Read 2 more answers

Find the multiplicity of 2x^3+x^2-x

OLEGan [10]

Mulitpilicty is how many times a root repeats

factor
factor x first

x(2x^2+x-1)
using math
(x)(x+1)(2x-1)
no roots repeat

if it is equal to 0 then the roots are
0 multiplicty 1
-1 multiplicty 1
1/2 multiplicty 1

4 0

3 years ago

Please help i have no clue

kozerog [31]

Answer:

Step-by-step explanation:

Question (1)

x² + 10x + 12

= x² + 2(5x) + 5² - 5² + 12

= [x² + 2(5x) + 5²] - 5² + 12

= (x + 5)² - 25 + 12 [Since, a² + 2ab + b² = (a + b)²]

= (x + 5)² - 13

Question (2)

y² - 6y - 15

= y² - 2(3y) - 15

= y² - 2(3y) + 3² - 3² - 15

= [y² - 2(3y) + 3²] - 3² - 15 [Since, a² - 2ab + b² = (a - b)²]

= (y - 3)² - 3²- 15

= (y - 3)² - 9 - 15

= (y - 3)² - 24

6 0

3 years ago

Solve for x (x/r)+(x/w)+(x/t)= 1

MissTica

x/r + x/w + x/t = 1

x (1/r + 1/w + 1/t) = 1

x = 1 / (1/r + 1/w + 1/t)

To make the solution a bit cleaner, multiply through the numerator and denominator by the LCM of each fraction's denominator, rwt :

x = 1 / (1/r + 1/w + 1/t) • rwt / rwt

x = rwt / (rwt/r + rwt/w + rwt/t)

x = rwt / (wt + rt + rw)

5 0

4 years ago

Please answer as soon as possible

OlgaM077 [116]

Answer:

30 cubic units³

Step-by-step explanation:

Given equation:

3 * 2 * 5

Solve for cubic units³

3 * 2 * 5
= 6 * 5
= 30

There are 30 cubic inches³.

Word form:

Three times Two Times Five
equals Six times Five
equals Thirty.

There are Thirty cubic inches³.

7 0

2 years ago

Read 2 more answers