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tamaranim1 [39]
4 years ago
5

-3 (c+4) – 2 >- 5I'm seriously confused ​

Mathematics
1 answer:
lawyer [7]4 years ago
6 0

Answer:

c < -3

Step-by-step explanation:

-3 (c + 4) – 2 > -5

Multiply both sides by -1 (don't forget to flip the sign):

3 (c + 4) + 2 < 5

Distribute:

3c + 12 + 2 < 5

Combine like terms:

3c + 14 < 5

Subtract 14:

3c < -9

Divide by 3:

c < -3

The solution is c < -3.

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Solve R=D-T/3 for the variable D
Ksivusya [100]

Answer:

D = \frac{3R+T}{3}

Step-by-step explanation:

given R = \frac{D-T}{3}

multiply all terms on both sides to eliminate the fraction

3R = 3D - T ( add T to both sides )

3R + T = 3D ( divide both sides by 3 )

D = \frac{3R+T}{3}


3 0
3 years ago
How do you add vectors? Add the vector &lt;3,4&gt; to the vector that goes 7 units at an angle of 2π/3.
lawyer [7]

Answer:

The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

Step-by-step explanation:

The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф

The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф

The vector is <b cos Ф , b sin Ф>

∵ The vector goes 7 units at an angle \frac{2\pi }{3}

- That means its magnitude is 7 and its direction is  \frac{2\pi }{3}

∴ x = 7 cos(  \frac{2\pi }{3} )

∴ y = 7 sin(  \frac{2\pi }{3} )

∵ cos(  \frac{2\pi }{3} ) =  -\frac{1}{2}

∵ sin(  \frac{2\pi }{3} ) =  \frac{\sqrt{3}}{2}

- Substitute them in x and y

∴ x = (7)( -\frac{1}{2} )

∴ x = -3.5

∴ y = (7)( \frac{\sqrt{3}}{2} )

∴ y = 3.5\sqrt{3}

∴ The vector is <-3.5 , 3.5\sqrt{3}>

Now lets add the vectors by adding xs and ys components

∵ <3 , 4> + <-3.5 , 3.5\sqrt{3} > = <3 + -3.5 , 4 + 3.5\sqrt{3} >

∴  <3 , 4> + <-3.5 , 3.5\sqrt{3}> = <-0.5 , 4+3.5\sqrt{3} >

∴ The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

5 0
4 years ago
Sum of the radius of the base and height of a cylinder is 21 cm and the curved surface area of the cylinder is 616 sq.cm,find th
Kobotan [32]

Step-by-step explanation:

lets radius be r and height be h,

r+h=21 -----(1)

curved surface area

2×pi×r×h=616 -----(2)

use simultaneous eqn to solve for r and h.

total surface area of cylinder= 2×pi×r×h + 2×pi×r²

= ans if im not wrong

4 0
3 years ago
Need help with the second part:
MaRussiya [10]

Answer:

  3.27 meters

Step-by-step explanation:

The given equation gives a y(0) = 0, for the deflection of 3 cm. Then for a deflection of 2.5 cm, we want y(x) = 0.005, half a centimeter above the low point on the beam. Using this value, we can solve for x:

  0.005 = 3/6400x^2

  32/3 = x^2

  4√(2/3) = x ≈ 3.26599 ≈ 3.27 . . . . meters

The deflection of the beam is 2.5 cm at a distance of 3.27 meters from center.

7 0
3 years ago
Lesson 2 Quiz Pleasee ❗️
FromTheMoon [43]

Answer:

True

Step-by-step explanation:

5 0
3 years ago
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