Need help with the second part:
1 answer:
Answer:
3.27 meters
Step-by-step explanation:
The given equation gives a y(0) = 0, for the deflection of 3 cm. Then for a deflection of 2.5 cm, we want y(x) = 0.005, half a centimeter above the low point on the beam. Using this value, we can solve for x:
0.005 = 3/6400x^2
32/3 = x^2
4√(2/3) = x ≈ 3.26599 ≈ 3.27 . . . . meters
The deflection of the beam is 2.5 cm at a distance of 3.27 meters from center.
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