Question

Find four consecutive even integers whose sum is 244

Answer 1

The four consecutive even integers will be expressed as

$n \\ n+2 \\ n+4 \\ n+6$

So, we have to add them up and simplify the equation made.

$n+n+2+n+4+n+6=244 \\ 4n+12=244 \\ 4n+(12-12)=(244-12) \\ 4n=232 \\ \frac{4n}{4}= \frac{232}{4} \\ n=58$

So, you just substitute 58 into the numbers

$n=58 \\ n+2=58+2=60 \\ n+4=58+4=62 \\ n+6=58+6=64$

The four consecutive even integers are 58, 60, 62 and 64.