Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
12x + 20
Step-by-step explanation:
2(4x + 6 +2x + 4)
In a game of rock paper scissors, what are the chances that someone playing against a person playing only paper would win?
As for the answer, if you were to make a chart to show rock, paper, and scissors, you'd be able to see that there's a 2/3 chance of winning by choosing rock. With scissors, there's also a 2/3 chance to win. Now with paper, there's only a 1/3 chance to win. Knowing that the other person will only play paper, the best answers would be to choose either rock or scissors.
(there are, of course, flaws with this concept, because the opponent could be lying about playing only paper. More or less, it's a good design to show probability.)
Answer:
10 km/h
Step-by-step explanation:
I'm not really sure about this but no ones answering your question and I wanna help.
So basically to calculate the average speed you need to divide the distance travelled by time taken
But you do not have the distance traveled. But it is mentioned that it takes u 30 minutes to walk from home to school when walking at 5 km/h so to find the distance all you have to do is... 30 x 5 = 150 km
Now that we have the time and distance all we have to do is find the average speed.
Average Speed = distance ÷ time
So 150 ÷ 15 = 10 km/h
1. The function

is a parabola of the form

. The the formula for the axis of symmetry of a parabola is

. We can infer from our function that

and

, so lets replace those values in our formula:





We can conclude that to the left of the line of symmetry the ball is reaching its maximum height, and to the right of the line of symmetry the ball is falling.
2. Lets check how much time the ball takes to reach its maximum height and return to the ground. To do that we are going to set the height equal to zero:



or


or

From our previous point we know that the ball reaches its maximum time at

, which means that <span>
it takes 1.5 seconds to reach the maximum height and 1.5 seconds to fall back to the ground.</span>