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Natali [406]
3 years ago
13

A recipe calls for 3 3/4 cups of flour. How much flour is needed to make 1/2 the recipe?

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
You would make that 1 7/8
You might be interested in
-11.
dalvyx [7]

Answer:

<em>A(2,3) has a distance of 2 to the y-axis</em>

<em>B(-3,2) has a distance of 3 to the y-axis</em>

<em>C(2,-3) has a distance of 2 to the y-axis</em>

<em>D(-3,-2) has a distance of 3 to the y-axis</em>

Step-by-step explanation:

<u>Distance of a point to an axis</u>

Given a point (x,y) its rectangular coordinates are defined as the distances from the point to each axis with respect to the origin (0,0).

For example, the point (5,4) has a distance of 5 from the y-axis and a distance of 4 from the x-axis.

Generally speaking, point (x,y) has a distance |x| from the y-axis and a distance |y| from the x-axis.

The absolute value bars are used because the distance is always positive.

Apply that to the points:

A(2,3) has a distance of 2 to the y-axis

B(-3,2) has a distance of 3 to the y-axis

C(2,-3) has a distance of 2 to the y-axis

D(-3,-2) has a distance of 3 to the y-axis

8 0
2 years ago
31)The scale on a map shows that 5 centimeters = 2 kilometers.
Sonbull [250]

Answer:

13.5 cm

Step-by-step explanation:

if 5 cm is 2 km, then 10 cm is 4 km. To find one km you do half of 5 cm. which is 3.5 cm. So 10+3.5=13.5

8 0
3 years ago
Two consecutive even intergers whose sum is 110
Harrizon [31]
Consecutive even integers are 2 apart
they are
x and x+2


sum is 110
x+x+2=110
2x+2=110
minsu 2 both sides
2x=108
divide both sidedse by 2
x=54
x+2=56
the numbers are 54 and 56
7 0
3 years ago
Tamara and Amir shared a candy bar. Tamara ate two fifths. Amir ate two fifths. How much is left?
marin [14]

Answer:

1/5

Step-by-step explanation:

Both Amir and Tamara ate 2/5 each.

2/5 + 2/5 = 4/5

If 4/5 of the candy bar was eaten, 1/5 of the candy bar remains because

5/5 - 4/5 = 1/5

(Remember that 5/5 just equals one whole, representing the whole candy bar)

7 0
3 years ago
Is -2 a solution to 4x^(3)-x^(2)+16x-4
sergiy2304 [10]

Answer:

Not a solution

Step-by-step explanation:

In order for x=-2 to be a solution, the result after substituting must be 0:

4(-2)^3-(-2)^2+16(-2)-4\stackrel{?}{=}0

4(-8)-4-32-4\stackrel{?}{=}0

-32-40\stackrel{?}{=}0

-72\neq0

Therefore, x=-2 is not a solution to 4x^3-x^2+16x-4

3 0
2 years ago
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