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snow_tiger [21]
3 years ago
12

Rachel has 8/12 of a fun of frosting. If she used 1/4 of it, how much was left?

Mathematics
2 answers:
astraxan [27]2 years ago
7 0

Answer:

5/12

Step-by-step explanation:

8/12=2/3

2/3-1/4=8/12-3/12=5/12

RoseWind [281]3 years ago
6 0

Answer:

6/12

Step-by-step explanation:

A fourth of 8 is 2, so there would be 6/12 of the tub of frosting left.

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Find the volume of the pyramid. Round your answer to the nearest hundredth.
dybincka [34]
I would say b hope this help ☺
8 0
3 years ago
Suppose you can afford only $200 a month in car payments and your best loan option is a 60-month loan at 3%. How much money coul
g100num [7]

Answer:

  $11,130.47

Step-by-step explanation:

The amortization formula can be used. It tells you the monthly payment amount A for some principal P, interest rate r, and n payments.

  A = P(r/12)/(1 -(1 +r/12)^(-n))

Filling in your values, we get ...

  200 = P(.03/12)/(1 -(1 +.03/12)^-60) = P(.0025)/(1 -1.0025^-60)

  P = 200(1 -1.0025^-60)/.0025 ≈ 200×55.6523577

  P ≈ 11,130.47

The present value of the loan is $11,130.47.

8 0
3 years ago
John goes running every morning. He can run 3 miles in 1 hour. How many miles would he be able to run in 1 and ½ hours? A. 4.5 m
BARSIC [14]

Answer:

2

Step-by-step explanation:

well less than 3

7 0
3 years ago
Read 2 more answers
Identify two segments that are marked congruent to each other on the diagram
Marat540 [252]

Answer:

segments LJ and LI are congruent

Step-by-step explanation:

look for the little lines (tick marks)

similar marks mean congruent to each other

5 0
3 years ago
Can someone please teach me how to do this? You can please do like 2 questions and please explain exactly how you got the answer
spayn [35]

All of these questions require one thing: trigonometric functions.

There are 3 main trigonometric functions, which can only be used on right triangles: sine, cosine, and tangent.

Sine = opposite / hypotenuse

Cosine = adjacent / hypotenuse

Tangent = opposite / adjacent

When trying to figure out what function to use, we always start by looking from the angle. Take problem a, for example. Looking from angle E, of which the value is not given, we have the side opposite and the side adjacent. Therefore, we should use the tangent function.

---The hypotenuse is always the longest side of the triangle. It is never considered the opposite or adjacent side.

Let's set up our function with the given information from problem a.

tan(x) = 9.7 / 5.2

---The tangent of an unknown angle is equal to the quotient of the opposite side and the adjacent side.

Now, solving for the value of x will require a calculator. We'll need to use what's called an inverse trigonometric function. Most calculators have these directly above the regular trigonometric functions, and the inverse functions are accessed using a "second" key.

---Ensure that your calculator is in degrees, not radians!

x = tan^-1(9.7 / 5.2)

x = 61.805 = 62 degrees

Next, let's take a look at problem b. This time, we're solving for a side length instead of an angle. But, we're still going to start by looking from our angle.


Looking from the 38 degree angle, we are given the adjacent side and an unknown hypotenuse. Therefore, we should use the cosine function.

cosine(38) = 53.1 / r

---The cosine of a 38 degree angle is equal to the quotient of 53.1 and an unknown hypotenuse, r.

Use your algebra skills to isolate the variable r.

r * cosine(38) = 53.1

r = 53.1 / cosine(38)

---From here, all you need to do is plug this into your calculator. Since we are solving for a side length (and given an angle), we are just using the regular trigonometric function buttons on the calculator.

r = 67.385 = 67.4 units

Hope this helps!

4 0
1 year ago
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