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3 years ago

9

The ends of a pipe when measured with a tape measure that has marks every millimeter are exactly at the 0 mark and the 15 meter

mark. how would you record this measurement keeping the correct number of significant figures.

1 answer:

exis [7]3 years ago

3 0

If the ends span from the 0 to the 15 meter mark, then the length of the pipe is 15 meters. However, you should report it using the right amount of significant figures. It is mentioned in the problem that millimeter marks are calibrated between meters. Since millimeter is 1/1000 of a meter, you should add three decimal places to the 15 meters. Hence, you should report it as 15.000 meters.

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Help me find y please

Andreyy89

Answer:

103

Step-by-step explanation:

it has to add up to 180 so

180-77=103

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2 years ago

Solving polynomial(2y-4)(3y+6)

jeka57 [31]

Answer:

6y² - 24

Step-by-step explanation:

Expand. Follow FOIL method. FOIL =

First

Outside

Inside

Last.

First, multiply the first term of each parenthesis:

2y * 3y = 6y²

Next, multiply the outside terms from both parenthesis:

2y * 6 = 12y

Then, multiply the inside terms from both parenthesis:

-4 * 3y = -12y

Finally, multiply the last terms of each parenthesis:

-4 * 6 = -24

Combine like terms:

6y² + 12y - 12y - 24

6y² + (12y - 12y) - 24

6y² - 24

6y² - 24 is your answer.

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3 0

3 years ago

Read 2 more answers

A figure is composed of a rectangle and a right triangle. What is the area of the figure?

strojnjashka [21]

QUESTION 1

The figure is a tra-pezoid.

The area of a trapezoid is given by the formula;

$A=\frac{1}{2}(Sum\:of\:parallel\:sides)\times h$

We substitute the values to obtain;

$Area=\frac{1}{2}(13.2cm+8.4cm)\times 6cm$

$Area=\frac{1}{2}(21.6cm)\times 6cm$

$Area=64.8cm^2$

QUESTION 2

The approximate length of the ribbon is equal to the circumference of the circular table cloth.

We can find this by using the formula for calculating the circumference of a circle.

$C=2\pi r$

where $r=3.5ft$ is the radius of the circular table cloth.

We substitute this value and $\pi=3.14$ into the formula to get;

$C=2(3.14)(3.5)ft$

$C=21.98ft$

The approximate length of the ribbon is 22.0ft to the nearest tenth.

QUESTION 3

Type of quadrilateral:Rectangle

Explanation: A rectangle has 4 angles that are right angles.

The two pairs of opposite sides of a rectangle are also congruent.

QUESTION 4.

The circumference of a semi circle is calculated using the formula;

$C=\pi r$

where $r=12.5cm$ is the radius of the semicircle.

$C=3.14\times 12.5cm$

$C=39.25cm$

QUESTION 5

The area of the entire figure is the area of the semicircle plus the area of the isosceles triangle.

$Area=\frac{1}{2}\pi r^2+\frac{1}{2}bh$

$Area=\frac{1}{2}\times3.14\times12.5^2+\frac{1}{2}\times25\times 24$

$Area=345.3125+300$

$Area=645.3125cm^2$

$Area\approx645cm^2$

QUESTION 6

The area of the parallelogram is given by the formula;

$A=bh$

From the diagram, $b=y\:in.,h=3in.$ .

Given, A=23.7 inches squared.

We substitute the values to obtain;

$23.7=3y$

$y=\frac{23.7}{3}$

$y=7.9in.$

QUESTION 7

The area of a rectangle is given by the formula;

$Area=l\times b$

The area of the bigger rectangle $=9\times15=135in^2$

The area of the smaller rectangle $=8\times 13=104in^2$

The area of the shaded region $=135-104=31in^2$

5 0

3 years ago

Suppose that a cyclist began a 364 mi ride across a state at the western edge of the state, at the same time that a car traveli

maw [93]

The car's average rate is 43.7 mph. The bicycle's average rate is 12.3 mph.

To get this solution, let the bicycle's average rate be (x) and the car's average rate be (x + 31.4) mph.

Distance= Speed x Time
364 = (x + x + 31.4) 6.5
364 = (2x + 31.4) 6.5
364/6.5 = 2x + 31.4
56 = 2x + 31.4
56 - 31.4 = 2x
24.6 = 2x
24.6/2 = x
12.3 = x

x = 12.3 mph
x+31.4 = 43.7 mph

6 0

3 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find (f - g)(x).

Marina86 [1]

Answer:

$\boxed{\sf (f - g)(x) = 2x - 3}$

Given:

f(x) = 3x - 1

g(x) = x + 2

To Find:

(f - g)(x)

Step-by-step explanation:

$\sf (f -g)(x) = f(x) - g(x) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =(3x - 1) - (x + 2) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3x - 1 - x - 2 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3x - x - 1 - 2 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =(3x - x) - (1 + 2) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =2x - (1 + 2) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =2x - 3$

6 0

3 years ago