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3 years ago

Please help with this

Mathematics

2 answers:

Firlakuza [10]3 years ago

8 0

Answer:

Number 1

Step-by-step explanation:

The equation is y^2+x^2=16 for the basic circle, so 4) is eliminated. Then, it goes down 1 y-unit and right 2 x-units, so 2) is eliminated as well. The reason 3 is wrong is because in an equation, when you add to the x then it goes left, and when you subtract from y it goes up. That means that only number 1 is a viable solution

Alborosie3 years ago

7 0

Option 1.
Radius is square root of 16 which is 4.
(x-2)^2, when set to zero means move right 2.
(y+1)^2, means move center down 1.
So the center should be (2,-1).

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Daniel wrote the following two-column proof for the given information.

Pavel [41]

The information given about the proof does that Daniel made an error on line 2.

<h3>How to illustrate the information?</h3>

Given:

1. AB = 3x +2; BC = 4x + 8; AC = 38

2. AB + BC = AC incorrect (not an angle angle addition postulate)

3. 3x+2 + 4x + 8 = 38 correct

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Daniel made an error on line 2.

Here is the complete question:

Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5

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Answer:

Step-by-step explanation:

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