Answer:
Answer in file:
Step-by-step explanation:
Answer: (x + 3)^2 + (y - 4)^2 = 49
Step-by-step explanation:
The equation of a circle given the center and radius: (x - h)^2 + (y - k)^2 = r^2
Given: center (-3,4) ; h = -3 and k = 4
diameter = 14
To find the radius: divide the diameter by 2 = 14/2 = 7 = r
Center: (-3,4) and radius: 7
Equation of a circle: (x - h)^2 + (y - k) ^2 = r^2
Substitute h = -3, k = 4, r = 7
(x - (-3))^2 + (y - 4)^2 = 7^2
Answer:
Equation of the circle: (x + 3)^2 + (y - 4)^2 = 49
Answer:
No solution
Step-by-step explanation:
There is not a real nor an imaginary solution to this equation. You can use a radical calculator to verify.
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
