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Sauron [17]
3 years ago
10

Solve this fraction:4\3+6\9-7\3,,,and simplified if it can simplify....

Mathematics
1 answer:
icang [17]3 years ago
4 0
4/3+6/9-7/3=12/9+6/9-21/9=18/9-21/9= -3/9= -1/3
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PLEASE HELP AND EXPLAIN! <br><br> A. y=60x <br> B. y=80x <br> C. y=10x<br> D. y= 6x
Rudik [331]

Answer:

C).

Step-by-step explanation:

One of the points on the graph that the path of bike b crosses is (6,60).

When you divide this to find the unit rate you get 10/1 therefore the equation of bike b= y+10X

8 0
3 years ago
If B = w + 10 and C = -w - 1, find an expression that equals B + 2C in standard form
enot [183]

Answer:

Step-by-step explanation:

B + 2C

= w + 10 + 2(-w - 1)

= w + 10 -2w - 2

= -w + 8

8 0
2 years ago
A gift basket has 2 soaps and 5 lotions and costs $20. A second basket has 6 spas and 15 lotions and cost $60. Is it possible to
kifflom [539]

A second basket has 6 spas--- I think you mean 6 soaps , so i will work with that

Answer:it is not possible to determine the price of the soap with the information given.

Step-by-step explanation:

Let s0ap be represented as x

and lotion be represented as y

2 soaps and 5 lotions costing  $20 gives us equation 1 as

2 x+ 5y= 20-------- equation 1

second basket with 6 soaps and 15 lotions and costing $60 gives us equation 2 as

6x + 15y= 60------equation 2

Step 2 -- Solving

2 x+ 5y= 20-------- equation 1

6x + 15y= 60--------equation 2

BY elimination method, we  multiply equation 1 by (3)

2x + 5y= 20  x (3)

6x + 15y=60-------equation 3

Subtraction of equation 3 from equation 2 gives us

6x + 15y=60-------equation 3

-6x + 15y= 60--------equation 2

0x +0y=0  which is no solution

Therefore it is not possible to determine the price of the soap

3 0
3 years ago
Some students were asked what kinds of animals they have at home.
Nataly_w [17]

(a) Animals by popularity; Dogs, Cats, Others, Horses.

(b) If 250 students were interviewed, 20 students have other pets.

(c) No, it was incorrect.

Step-by-step explanation:

Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;

1. Dogs - 67%,

2. Cats - 20%

3. Others - 8%,

4. Horses - 1%.

None is not included in this list.

Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.

8% of 250 = \frac{8}{100} × 250 = 0.08 × 250 = 20.

So 20 students had other pets.

Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.

20% × x = 75, 0.2 × x = 75,

x = \frac{75}{0.2} = 375.

So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.

8 0
3 years ago
A doctor's office has a computer file showing the heights of 100 male patients of one of the doctors of the practice. the height
kumpel [21]
A) Yes. we don't have enough information so this can not be determined.
B) No, it would just be an outlier.
7 0
3 years ago
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