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nadya68 [22]
3 years ago
13

Hey good morning I need help ASAP thank you guys

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

B. x = 2.77

Step-by-step explanation:

3^x = 21

You first look for a base for 21 that is 3 to the power of something.

21 = 3^2.77

So 3^x = 2^2.77

They have the same base so

x= 2.77

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Hello from MrBillDoesMath!

Answer:

No. That problem cited is one of 3 great unsolved problems of antiquity. See  https://en.wikipedia.org/wiki/Angle_trisection for details.


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who
Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0
3 years ago
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