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Arlecino [84]
3 years ago
13

(x^2-5x+2) (3x^2+2x+3)

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0
3X^4-13x^3-x^2-11x+6
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2+d=2-3(d-5)-2 Pls show work
defon
2 + d = 2 - 3(d- 5) - 2

First, cancel 2 on both sides. / Your problem should look like: d = -3(d - 5) - 2
Second, expand. / Your problem should look like: d = -3d + 15 - 2
Third, simplify -3d + 15 - 2 to get -3d + 13. / Your problem should look like: d = -3d + 13
Fourth, add 3d to both sides. / Your problem should look like: d + 3d = 13
Fifth, add d + 3d to get 4d. / Your problem should look like: 4d = 13
Sixth, divide both sides by 4. / Your problem should look like: d =  \frac{13}{4}

Answer as fraction: d =  \frac{13}{4}
Answer as decimal: d = 3.25

3 0
3 years ago
Read 2 more answers
A community orchestra is losing money. They have always sold tickets for
-Dominant- [34]

Answer:

Step-by-step explanation:

I think it's a or b

7 0
3 years ago
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Plssssss heeeelp (NOOOOO LINKS!)
ahrayia [7]
-40) No
0) No
-5) No
13) Yes
21)Yes
8 0
3 years ago
Please help asap :( This is my "Final grade" My Teacher wants a full explanation included ! on how i got the answer. )
Mrac [35]

If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)

The total volume of the ball will be;

= Total volume - Volume of hollow part

= 4/3πr³ - 4/3πr³

= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³

= 4 × 3.14 × 9 - 4/3 × 3.14 × 8

= 113.04 - 33.52

= 79.52

If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;

= 79.52 × 3.25

= 258.44 g

Now, if there are 8 spheres in one box, the weight if box will be;

= 258.44 × 8

= 2,067.52 g

_____________________________

Ahh! Finally done with this, if you have any doubt just do ask me :)

3 0
3 years ago
Problem:
BARSIC [14]

Answer:

(c) Equation  which can be used to find r, the cost in dollars to park s nights is  r = 24.99 s

Step-by-step explanation:

Here, the parking cost of 1 night at the airport  = $24.99

Now, here the total number of nights the car is parked at airport = s

R = The total cost of parking s nights

Now, The cost for parking s nights  = s x ( Cost of parking 1 night)

= s x ($24.99) = 24.99 s

Also the cost for parking s nights    = r

⇒  r = 24.99 s

Hence, equation  which can be used to find r, the cost in dollars to park s nights is  r = 24.99 s

4 0
3 years ago
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