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2 years ago

How do you turn a ratio into a percentage number

Mathematics

1 answer:

lilavasa [31]2 years ago

3 0

To convert a ratio to a percentage you have to divide then multiply by 100!
Hope this helps

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Find the quotient. 1. (a a 8. 2

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Answer:

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2 years ago

Substitution again help please

Vesnalui [34]

Answer:

Step-by-step explanation:

1) 4x -3

x = -7 ;

4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31

x = 14 ;

4x - 3 = 4*14 - 3 = 56 - 3 = 53

x = 0

4x - 3 = 0 - 3 = -3

2) 6 -3x

x = -7 ;

6 - 3x = 6 - 3*(-7) = 6 + 21 = 27

x = 14

6 - 3x = 6 - 3*14 = 6 - 42 = -36

x = 0

6 - 3x = 6 - 0 = 6

$3) \dfrac{3x - 21}{7}\\\\x = -7\\\\\\\dfrac{3*(-7)-21}{7}=\dfrac{-21-21}{7}=\dfrac{-42}{7}=-6\\\\\\x = 14\\\\\dfrac{3*14-21}{7}=\dfrac{42-21}{7}=\dfrac{21}{7}=3\\\\\\x=0\\\\\dfrac{0-21}{7}=\dfrac{-21}{7}=-3\\\\$

$\dfrac{3x}{7}-21\\\\\\x = -7\\\\\dfrac{3*(-7)}{7}-21=-3-21=-24\\\\\\x =14\\\\\dfrac{3*14}{7}-21=3*2-21=6-21=-15\\\\\\x=0\\\\\dfrac{0}{7}-21=-21$

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2 years ago

in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume

Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

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2 years ago

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nika2105 [10]

Answer:

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