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goblinko [34]
3 years ago
15

Any help please asap

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0
The answer will be b

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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

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3 years ago
What is the distance of a car traveling with a velocity of 20 m/s north in 5 seconds
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(time)

20(5)

=100m/S

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Rolf spent 15 hours last week practicing his saxophone if 3/10 of the time was spent practicing warm up routines, how much time
NeTakaya
3/10 of the time = time spent on practicing warm up routines...
Time spent = 15 hours
remember that 'of' is usually multiply (x)
so ---- 3/10 x 15 =4.5 hrs

Hope this helps
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State if the triangles in each pair are similar. If so, state how you know they are similar and complete the similarity statemen
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Answer:

please give me brainliest for quest

Step-by-step explanation:

7 0
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\texttt{Length of the arc }= 2\pi R\times  \frac{10}{360} = \frac{2\pi \times 10}{36} = \frac{20\pi}{36} =  \boxed{\frac{5\pi}{9}~m}



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