3 years ago

Plzzzzzzz helppppppp meeeeeee

Mathematics

1 answer:

evablogger [386]3 years ago

5 0

The answer would be 1/4! :)

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The equation for a parabola has the form y=ax2+bx+c, where a, b, and c are constants and a≠0. find an equation for the parabola

IRISSAK [1]

The equation of parabola is

$y= ax^2 + bx +c$

For point (-1,-9), equation of parabola is

$-9 = a(-1)^2 +b(-1)+c
\\
-9 = a -b+c$

For point (1,7), equation of parabola is

$7 = a(1)^2 + b(1)+c
\\
7 = a + b +c$

For point (-6,-14), equation of parabola is

$-14 = a(-6)^2 +b(-6)+c
\\
-14 = 36a -6b +c$

So we have three equations , which are

$a - b + c =-9,
\\
a + b + c = 7
\\
36a -6b+c = -14$

Subtracting first two equation will give

$-2b = -16
\\
b=8$

Subtracting second and third equation gives

$a+b+c-36a+6b-c = 7+14
\\
-35a +7b = 21
\\
-5a + b =3$

Substituting 8 for b, we will get

$-5a + 8 =3
\\
-5a = -5
\\
a =1$

back substituting 8 for b and 1 for a, we will get

$1+8+c = 7
\\
c = -2$

So we have

$a=1, b=8 and c=-2$

Therefore required equation is

$y= x^2 +8x-2$

7 0

3 years ago

Im really confused can someone help me

Sati [7]

I believe you would create and equation to find x and y.

7 0

3 years ago

I need help on this maybe asap. its been a long day.

aivan3 [116]

Answer:

yoo thanks u the goat

Step-by-step explanation:

5 0

3 years ago

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TIME REMAINING

irakobra [83]

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700th

Step-by-step explanation:

vhzjjb zetas CD kinda cos dsuskskxn BBC bxhxjcjjdjdjjcfjjfjfjbdhduudjthfhhff&hdjdjjff#jfjjffj#

#enaa garntiii

8 0

3 years ago

Evaluate.<br><br> 33+1⋅9+12 <br><br> please help!

jasenka [17]

54 is ur answer :)))))))

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3 years ago

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Plzzzzzzz helppppppp meeeeeee​

Plzzzzzzz helppppppp meeeeeee