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Elodia [21]
3 years ago
14

How to answer this in interval notation? x+1/x+7 is less than or equal to 0

Mathematics
1 answer:
Phoenix [80]3 years ago
3 0
The answer is (-7,-1) you just need to convert the inequality
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What is the present value of $9,000 paid at the end of each of the next 86 years if the interest rate is 10% per​ year? the pres
Fittoniya [83]

It will be $900

Hope it helps!

6 0
3 years ago
Marco and Drew stacked boxes on a shelf. Marco lifted 9 boxes and Drew lifted 14 boxes. The boxes that Drew lifted each weighed
MrRa [10]
The correct answer is b. 14(m-8).

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8 0
3 years ago
Convert this rational number to its decimal form and round to the nearest thousandth 5/7
Ksju [112]

The rational number, 5/7 converted to a decimal is 0.714.

<h3>What is the decimal?</h3>

A rational number is a number that can be expressed as a fraction of two integers.

A decimal is a non-integer in which the integers are separated from the non integers by a point. In order to convert the fraction to a decimal, divide the numerator by the denominator.

5/7 = 0.714

To learn more about rational numbers, please check: brainly.com/question/20435423

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6 0
2 years ago
Use the quadratic formula to solve the equation <br><br> x^2-3x+2=0
Flura [38]

Answer:

x= 1, 2

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=1, b=-3, and c=2.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{3+/-\sqrt{(-3)^2-4(1)(2)} }{2(1)}=\frac{3+/-\sqrt{9-8} }{2)}

\frac{3+/-\sqrt{1} }{2}=\frac{3+/-\sqrt{1} }{2}=\frac{3+/-1 }{2}= 2 , 1

3 0
3 years ago
How would you verify the trigonometric identity 2x = 2sinx cosx
dem82 [27]

Step-by-step explanation:

<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>sin2x</em><em>=</em><em>2</em><em>sinx</em><em> </em><em>.</em><em> </em><em>cosx</em>

<em>so</em><em>,</em><em> </em><em>let's</em><em> </em><em>begin</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>simple</em><em> </em><em>way</em><em>;</em><em> </em><em>by</em><em> </em><em>adding</em><em>,</em><em> </em><em>alright</em><em>:</em>

<em>sin2x</em><em>=</em><em> </em><em>sin</em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>as</em><em> </em><em>2</em><em>x</em><em>=</em><em>x</em><em>+</em><em>x</em><em>)</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>let's</em><em> </em><em>use</em><em> </em><em>compound</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>sin</em><em>,</em>

<em>so</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em>:</em>

<em>sin</em><em> </em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em>=</em><em> </em><em>sinx.cosx</em><em> </em><em>+</em><em> </em><em>cosx</em><em>.</em><em> </em><em>sinx</em><em> </em><em> </em><em> </em><em>(</em><em>as</em><em> </em><em>sin</em><em>(</em><em>A</em><em>+</em><em>B</em><em>)</em><em>=</em><em>sin</em><em> </em><em>A</em><em>.</em><em> </em><em>cosB</em><em> </em><em>+</em><em> </em><em>cosA</em><em> </em><em>.</em><em> </em><em>sinB</em><em>)</em>

<em>or</em><em>,</em><em> </em><em>sin</em><em> </em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em>=</em><em>2</em><em>sinx</em><em>.</em><em>cosx</em><em> </em><em> </em><em>(</em><em>adding</em><em> </em><em>both</em><em>)</em><em>.</em>

<em>Therefore</em><em>, </em><em> </em><em>sin</em><em> </em><em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>2sinx</em><em>.</em><em> </em><em>cosx</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
Read 2 more answers
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