Answer: where’s the photo/attachment??
Step-by-step explanation:
Answer:
k=2
Step-by-step explanation:
3^k*2 * 3^-k+2 = 81
Factor out 81 to be : 3^4
Rewrite the equation:
k*2 - k+2 = 4
k^2 - 2k = 4
Simplify : k+2 = 4
<u> - 2 - 2</u>
k = 2
Answer:
0.321233-cups, 0.321233-tablespoon, 0.321233-teaspoon
Step-by-step explanation:
the next 2 questions I can't convert because I don't have grams
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.