We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
You would start by 6÷3. This would tell you that for every proud of hamburger you pay $2.
Therefore multiply 10×2 and that equals 20.
Therefore, your answer is $20.
A) 14.66
Arc length is equal to radius multiplied by the central angle in radians not degrees
<u>Answer:</u>
B. He multiplied the dividend by 100 instead of 10.
<u>Step-by-step explanation:</u>
Chen had to divide
by
. To make it easier to divide, he thought of multiplying both the dividend and the divisor by 10.
Chen multiplied the divisor by 10 but mistakenly multiplied the dividend by 100 instead of 10.
So his whole division problem was changed.
Therefore, the correct answer option is B. He multiplied the dividend by 100 instead of 10.