The line parellel to 2x+y=5 and passing through (5,4) has equation
1 answer:
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The given function is a variable separable differential equation. Combine like terms, integrate, apply the appropriate limits, and express V in terms of t. This is done as follows:
dV/dt = -3(V)^1/2
dV/-3V^1/2 = dt
m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t
-2/3 (√V - 15) = t
That is the expression for V at time t. I hope I was able to help. Have a good day.
dV/dt = -3(V)^1/2
dV/-3V^1/2 = dt
m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t
-2/3 (√V - 15) = t
That is the expression for V at time t. I hope I was able to help. Have a good day.
Answer:
D
Step-by-step explanation:
The expression is
We can follow the rule of "PEMDAS" here.
PEMDAS = Parenthesis, Exponents, Multiply, Divide, Add, Subtract
So, we first need to deal with Parenthesis. Next,
There aren't any exponents, so we deal with Multiplication of 7 and 3.
Then addition/subtraction.
Hence, the first step, from the answer choices, would be D, multiply 7 and 3