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barxatty [35]
3 years ago
10

The line parellel to 2x+y=5 and passing through (5,4) has equation

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Answer:

y=-2x+14

Step-by-step explanation:

If we are looking for a line parallel to 2x+y=5.

Then we are looking for an equation with the same slope as the equation 2x+y=5.

To obtain the slope of equaiton 2x+y=5 I will put it in slope-intercept form.

Luckily there is only one step which is to subtract 2x on both sides.

y=-2x+5

The slope of this line is -2

The slope of parallel line will also be -2.

So we know our equation is in the form y=-2x+b

To find b we will just use the point (x,y)=(5,4) we know is on the line.

Plug in and solve for b.

4=-2(5)+b

4=-10+b

14=b

So the equation that is parallel to 2x+y=5 and goes through (5,4) is y=-2x+14

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What set does 4/5 belong in
dem82 [27]

Answer:

Natural numbers are the counting numbers, meaning that they make up the set {1,2,3,4,5,...} So , 4/5 is belong to natural number

3 0
1 year ago
Can Someone Answer My Final Answers :) I’d appreciate it so much :)
DaniilM [7]
1. Remember that the perimeter is the sum of the lengths of the sides of a figure.To solve this, we are going to use the distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
(x_{1},y_{1}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point
Length of  WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}
d_{WZ}= \sqrt{(3)^2+(2)^2}
d_{WZ}= \sqrt{9+4}
d_{WZ}= \sqrt{13}

We know that all the sides of a rhombus have the same length, so 
d_{YZ}=  \sqrt{13}
d_{XY}= \sqrt{13}
d_{XW}= \sqrt{13}

Now, we just need to add the four sides to get the perimeter of our rhombus:
perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}
perimeter=4 \sqrt{13}
We can conclude that the perimeter of our rhombus is 4 \sqrt{13} square units. 

2. To solve this, we are going to use the arc length formula: s=r \alpha
where
s is the length of the arc. 
r is the radius of the circle.
\alpha is the central angle in radians

We know form our problem that the length of arc PQ is \frac{8}{3}  \pi inches, so s=\frac{8}{3} \pi, and we can infer from our picture that r=15. Lest replace the values in our formula to find the central angle POQ:
s=r \alpha
\frac{8}{3} \pi=15 \alpha
\alpha =  \frac{\frac{8}{3} \pi}{15}
\alpha = \frac{8}{45} \pi

Since \alpha =POQ, We can conclude that the measure of the central angle POQ is \frac{8}{45} \pi

3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut  in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section. 
We can conclude that the draw of our cross section is:

6 0
3 years ago
Read 2 more answers
A stone is launched into the air from a height of 240 feet. The height, h, of the stone, in feet, t seconds after launch is give
rosijanka [135]

A projectile is an object <u>launched</u> into space, and moving under the <em>influence</em> of <u>gravity</u> and <u>momentum</u>. The <em>stone</em> here is an example. Thus, the <em>time</em> taken for the stone to reach the ground is 10 seconds.

On <em>launching</em> of the stone into <u>space</u>, it behaves as a <u>projectile</u>. Thus moving under the <em>influence</em> of gravity and its momentum. Its <u>momentum</u> is the <em>product</em> of its <u>mass </u>and <u>velocity</u>.

The height h, is given as:

h = 16t^{2} + 32t + 240

Differentiating the expression with respect to t, we have;

32t + 32 = 0

t = -1 seconds

Substitute the value of time, t, in the equation for the height;

h = 16 - 32 + 240

  = 224

h = 224 m

Total height, S = 240 + 224

                         = 464

S = 464 m

The total height covered by the stone is 464 m.

From the second equation of <em>free fall</em>,

S = Ut + \frac{1}{2}gt^{2}

S = \frac{1}{2}gt^{2}

464 = \frac{1}{2}*9.8*t^{2}

t^{2} = \frac{928}{9.8}

  = 94.694

t = \sqrt{94.694}

 = 9.7311

t ≅ 10 seconds

The <em>time taken</em> for the stone to hit the ground is 10 seconds.

Thus option A is the required answer.

Visit: brainly.com/question/13834669

7 0
2 years ago
Please do it in substitution method. Thanks.​
alina1380 [7]

Answer:  No solution

<u>Step-by-step explanation:</u>

x - 3y = 2   →     x = 3y + 2

2x - 6y = 6

2(3y + 2) - 6y = 6        <em>substituted x with 3y+2</em>

6y + 4 - 6y = 6            <em>distributed 2 into 3y+2</em>

        4        = 6           <em>simplified (6y - 6y = 0)</em>

4 = 6 is a FALSE statement so there is NO SOLUTION

5 0
3 years ago
In the figure above, sin 52=17/c. Based on the figure, which of the following equations is also true
hram777 [196]

Answer:

c. Cos 52 = 17/c

Step-by-step explanation:

sin(x) = cos(90-x)

3 0
3 years ago
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