Check the picture attached.
Let OB be the radius of circle with center O.
Let B' be the image of B after the described rotation
OB and OB' are sides of the equilateral triangle OBB'.
The x coordinate of B' is the midpoint of OB, that is 5.
In the right triangle B', point (5, 0) and B:
Distance point (5, 0) to B is 5
|B'B|=|OB|=10
so by the pythagorean theorem:

units
Answer:
Answer:
2x² - 14x + 24
Step-by-step explanation:
Use the FOIL method (First, Outside, Inside, Last).
First, multiply the first term of both parenthesis:
2x * x = 2x²
Next, multiply the outside terms of both parenthesis:
2x * -4 = -8x
Then, multiply the inside terms of both parenthesis:
-6 * x = -6x
Finally, multiply the last terms of both parenthesis:
-6 * -4 = 24
Combine like terms:
2x² - 8x - 6x + 24
2x² (-8x - 6x) + 24
2x² (-14x) + 24
2x² - 14x + 24 is your answer.
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Answer:
Remainder is 691.
Step-by-step explanation:
Given function is
.
Now we need to find remainder if we divide given function
by (x-3)
(x-3) means plug x=3 into
to find remainder.







Hence remainder is 691.
I think option for the (D)
H(2)=x²=2²=4
G[H(2)]=G(4)=3(4)+2=12+2=14
F[G[H(2)]]=F(14)=2(14)-1=28-1=27
Answer: F[G[H(2)]]=27