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azamat
3 years ago
8

Please answer the question in the picture below

Mathematics
1 answer:
Elanso [62]3 years ago
5 0
The answer is b because there is a negative in the exponent and the number needs to be a single digit and 54 is double digit. hope this helps!
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MARKING BRANLIEST!!
grin007 [14]
Area of a triangle is = 0.5bh
if the height (h) is 4 less than base (b) then h = b - 4

48 = 0.5(b)(b - 4)
48/0.5 = b² - 4b
96 = b² - 4b
b² - 4b - 96 = 0
(b + 8)(b - 12) = 0

b must be either -8 or 12

since a distance can't be negative that means
the base is 12
6 0
3 years ago
On a certain standardized test used for college entrance purposes, the mean score was 21 and the standard deviation was 5. The d
Fiesta28 [93]

Answer:

A

Step-by-step explanation:

Carlos' score was 2 standard deviations from the mean, so his z-score was 2.0. You can either use the empirical 68-95-98.5 rule, or you can plug it into your calculator as <u>normalcdf(-999, 2) = .977</u>

So 97.7% of people had a score lower than Carlos!

.977 * 1.5 million = 1,465,500 people

5 0
3 years ago
T midnight, a candle was lit. At 15 minutes past midnight, the candle was 4 inches tall, and you notice that it burns at a rate
anyanavicka [17]

Answer:

a)   t-4 = 3 (i - 1/4h) =  h = 3i - 3 3/4h  

= t = -0.75

= h = 4  

b) 3.30am = 1 inch.

Step-by-step explanation:

a)   formula for point slope form = y - y1 = m(x-x1)

a) t-4 = 3(i - 1/4h)  converts to  t-4   = 3i - 3/4h  = t = 3i- 3 3/4

x = - 0.75 y = 4  =     t= -0.75 and h = 4

b) 12.15am = 4 inches

1.15am = 3.25 inches

2.15am = 2.5 inches

3.15am = 1.75inches

3.30 = 1 inches

3.15 + 15mins = 1 inch

6 0
3 years ago
Which of the following has a circular cross section when the cross section is taken parallel to the base?
zubka84 [21]
A.




Cone



(I’m for sure I’m right could I possiblely get brainliest?)
4 0
3 years ago
The height of a triangle is 3cm less than twice the base. The area is 10cm2
Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

This is a solve the system question. Call H the height of the triangle and B the base. The question tells us:

H=2B-3

and

\frac{B \times H}{2}=10

Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4

In this question, we take B=4. You can't have a negative side length so the other answer is eliminated. Now sub the value for B into either of the original equations. I'll use the first, again because H is already isolated:

H=2(4)-3\\H=8-3\\H=5

3 0
3 years ago
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