Since , the relation is linear .
Let equation is y = mx + c .
Putting , x = 0 and y = 32 .
32 = c .......( 1 )
Also , putting x = 100 and y = 212 .
We get :
212 = 100m + c .......( 2 )
Comparing equation 1 and 2 .
100m = 212 - 32
x = 1.8
Therefore , y = 1.8x + 32 .
Hence , this is the required solution .
Answer:
- 3.027
Step-by-step explanation:
First price = 10000 ; second price = 700
Number of tickets sold = 11000
Ticket cost = $4
Probability that a ticket wins grand price = 1 / 11000
Probability that a ticket wins second price = 1 / 11000
X ____ 10000 _____ 700
P(x) ___ 1 / 11000 ___ 1/11000
Expected winning for a ticket buyer :
E(X) = Σx*p(x)
E(X) = (1/11000 * 10000) + (1/11000 * 700) - ticket cost
E(X) = 0.9090909 + 0.0636363 - 4
E(X) = - 3.0272728
E(X) = - 3.027
Answer:
- $70
- y = 25 + 0.9x
- $250
Step-by-step explanation:
1. 10% of $50 is $5, so the purchases would come to $50 -5 = $45. Added to the $25 membership fee, the total cost for the year would be
$45 +25 = $70
2. The member pays $25 even if no purchases are made. Then any purchases are 100% - 10% = 90% of the marked price. So, the total is ...
y = 25 + 0.90x
3. $25 is 10% of $250, so that is the amount the member would have to purchase to break even on cost.
If you like, you can compare the cost without the membership (x) to the cost with the membership (25+.9x) and see where those costs are equal.
x = 25 +0.9x . . . . . x is the spending level at which there is no advantage
0.1x = 25 . . . . . . . . subtract 0.9x
25/0.1 = x = 250 . . . divide by 0.1
Answer:
google maybe
Step-by-step explanation:
.
Answer:
The ramp must cover a horizontal distance of approximately 19.081 feet.
Step-by-step explanation:
Given the vertical distance (
), measured in feet, and the angle of the wheelchair ramp (
), measured in sexagesimal degrees. The horizontal distance needed for the ramp (
), measured in feet, is estimated by the following trigonometrical expression:
(1)
If we know that 
and 
, then the horizontal distance covered by this ramp is:
The ramp must cover a horizontal distance of approximately 19.081 feet.
