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Marizza181 [45]
3 years ago
11

Anothony has 24 squash plants and 18 corn seedlings that he plans to plant in rows on his vegetable garden. Each row will contai

n only one type of plant, and he want me to have the same number of plants in each row of the garden. Anthony also wants to have the greatest number of plants possible in each row. What does Anthony need to find determine how many of each type of plant to put in each row? Explain
Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0

Anthony needs to find the greatest common factor of both 18 and 24. The reason why is because this way he can have the same number of plants in each row while having the greatest number in each row possible. The amount of plants he needs to put in each row is 6.

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If I want to make some teddy bear slippers and I wear I size 8 in shoes what inch of bear should I get
weqwewe [10]

Answer:

96 inches

Step-by-step explanation:

4 0
3 years ago
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


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4 years ago
In AABC, AC - BC. The length of AC is three times the length of AB. Find
Arlecino [84]

Answer:

i don't undertsand this question

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7 added to the product of 14 and f
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14f + 7

“Product” means multiplication, so we can assume 14 and f are being multiplied (14f.) Add that to 7, and you have an expression! Have a great day.
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What is the point called where the perpendicular bisectors of the sides of a triangle intersect
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