Answer:
Solution:
According to the Pythagorean Theorem, is that the square of the hypotenuse is equal to the sums of squares of the two legs in which if you take the square root of the sum you are going to get the actual length of the hypotenuse but the two legs are already squared so all you have to do now is sum them and take the square root of it.
Answer:
£142 for 3 jumpers and 8 T-shirts
Step-by-step explanation:
Since the T-shirts cost £3.50 each and they are buy one get one free, when you buy 8 T-shirts you only pay for 4 of them.
£3.50(4) = £140 for the 8 T-shirts
Since you bought 3 jumpers with a buy 3 for £2 sale, the 3 jumpers cost £2.
Add the amount of money all together to find the total cost of the T-shirts and jumpers.
£140 + £2 = £142
If this answer is correct, please make me Brainliest!
The answer is d because the x value does not repeat. Hopes this helps.
I will use the letter x instead of theta.
Then the problem is, given sec(x) + tan(x) = P, show that
sin(x) = [P^2 - 1] / [P^2 + 1]
I am going to take a non regular path.
First, develop a little the left side of the first equation:
sec(x) + tan(x) = 1 / cos(x) + sin(x) / cos(x) = [1 + sin(x)] / cos(x)
and that is equal to P.
Second, develop the rigth side of the second equation:
[p^2 - 1] / [p^2 + 1] =
= [ { [1 + sin(x)] / cos(x) }^2 - 1] / [ { [1 + sin(x)] / cos(x)}^2 +1 ] =
= { [1 + sin(x)]^2 - [cos(x)]^2 } / { [1 + sin(x)]^2 + [cos(x)]^2 } =
= {1 + 2sin(x) + [sin(x)^2] - [cos(x)^2] } / {1 + 2sin(x) + [sin(x)^2] + [cos(x)^2] }
= {2sin(x) + [sin(x)]^2 + [sin(x)]^2 } / { 1 + 2 sin(x) + 1} =
= {2sin(x) + 2 [sin(x)]^2 } / {2 + 2sin(x)} = {2sin(x) ( 1 + sin(x)} / {2(1+sin(x)} =
= sin(x)
Then, working with the first equation, we have proved that [p^2 - 1] / [p^2 + 1] = sin(x), the second equation.
Answer:
1
Step-by-step explanation: