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2 years ago

If the sides of a square are increased by 3 inches, the area becomes 64

Mathematics

1 answer:

seropon [69]2 years ago

4 0

Answer:

$Length\ of\ the\ side=5\ inches$

Step-by-step explanation:

Let x be the length of the sides of the original square.

Given:

The sides of a square are increased by 3 inches, the area becomes 64

So, the length of the side $x+3$

The area of the square is

$Area=(length\ of\ the\ side)^{2}$

$Area=(x+3)^{2}$

Substitute area value in above equation.

$64=(x+3)^{2}$

$(x+3)=(64)^{\frac{1}{2}}$

$x+3=\sqrt{64}$

$x+3=\sqrt{8^{2}}$

$x+3=8$

$x=8-3$

$x=5\ inches$

Therefore, the length of the sides of the original square is 5 inches.

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a_sh-v [17]

I FOUND YOUR FULL QUESTION IN OTHER FUENETES.
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For this case what you should do is find the area of the triangle which will be given by:
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Answer:
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3 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

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Step-by-step explanation:

step 1

Simple interest

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

Interest compounded annually

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

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$A=\$3,330.55$

step 3

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$A=\$3,330.55-\$3,150=\$180.55$

5 0

3 years ago

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Ksivusya [100]

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