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Ulleksa [173]
3 years ago
13

If the sides of a square are increased by 3 inches, the area becomes 64

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

Length\ of\ the\ side=5\ inches

Step-by-step explanation:

Let x be the length of the sides of the original square.

Given:

The sides of a square are increased by 3 inches, the area becomes 64

So, the length of the side x+3

The area of the square is

Area=(length\ of\ the\ side)^{2}

Area=(x+3)^{2}

Substitute area value in above equation.

64=(x+3)^{2}

(x+3)=(64)^{\frac{1}{2}}

x+3=\sqrt{64}

x+3=\sqrt{8^{2}}

x+3=8

x=8-3

x=5\ inches

Therefore, the length of the sides of the original square is 5 inches.

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79=11x+13 <br> Solve each equation by using the properties of equality and justify each step
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Detailed explanation:

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To finish this off, divide both sides by -11.

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Voila! There's our answer!

<h2><em>Cheers!! ^-^</em></h2>

___________________

Hope I helped.  Best wishes.

Reach far. Aim high. Dream big.

___________________

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