A student solves the following equation for all possible values of x:
2 answers:
Given 
Then the solution follows thus:
<span>Step 1: 8(x – 4) = 2(x + 2)
Step 2: 4(x – 4) = (x + 2)
Step 3: 4x – 16 = x + 2
Step 4: 3x = 18
Step 5: x = 6</span>
It can be seen that his solution is correct. But 6 is not an extraneous solution.
<span>
An extraneous solution is a solution to an equation that emerges from the process of solving the problem but is not a valid solution to the original problem.</span>
When 6 is substituted into the original equation, the original equation holds.
Therefore, h<span>is solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.</span>
Then the solution follows thus:
<span>Step 1: 8(x – 4) = 2(x + 2)
Step 2: 4(x – 4) = (x + 2)
Step 3: 4x – 16 = x + 2
Step 4: 3x = 18
Step 5: x = 6</span>
It can be seen that his solution is correct. But 6 is not an extraneous solution.
<span>
An extraneous solution is a solution to an equation that emerges from the process of solving the problem but is not a valid solution to the original problem.</span>
When 6 is substituted into the original equation, the original equation holds.
Therefore, h<span>is solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.</span>
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Answer:
U₂₁ and U₂₂ fits in the line of upper triangular
Step-by-step explanation:
As explain in the question
An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.
(as shown in the attached image)
(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular
for a matrices U (having a 3*3 matrix), assuming for example, U is given below:
U =
the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)
while lower triangular are 0,0,0, the element in the lower triangular are (U₂₁, U₃₁,U₃₂)
U₂₁ and U₂₂ fits in the line of upper triangular
