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Fiesta28 [93]
3 years ago
12

The sum of two numbers is 61. The larger number is17 more than the smaller number. What are the numbers? i need to find the smal

l and large number can someone help me find them
Mathematics
2 answers:
aksik [14]3 years ago
7 0

Answer:

22 and 39.

Step-by-step explanation:

Let x be the smaller number.

The larger number is 17 more than the smaller number.  

Larger = x + 17

The sum of two numbers is 61.

x+(x+17)=61

2x+17=61

Subtract 17 from both sides.

2x=61-17

2x=44

Divide both sides by 2.

x=\dfrac{44}{2}

x=22

Smaller number is 22. So, the larger number is

x+17=22+17=39

Therefore, the two numbers are 22 and 39.

pychu [463]3 years ago
4 0
Let x= small  number
x+17= larger
add them since together they equal 61
x+x+17=61
combine like terms
2x+17=61
2x= 44
divide by 2
x=22 which is the small number
22+17= 39 which is the larger number

hope this helps
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Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so n = 200.

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So \pi = 0.0995.

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find P(X < 18), with \pi = 0.0995, n = 200. We can use a binomial probability calculator, and we find that:

P(X < 18) = 0.2927.

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5 0
3 years ago
Only t circled ones somebody plz help I am gonna get a 0 plz help I will give you brainleist
Vikki [24]

Step-by-step explanation:

1) A number <em>m</em> is at least four

<em>m ≥ 4  ['at least' = ≥ symbol]</em>

<em />

2) 4x  ≤ 20x; x=2

4(2) ≤ 20(2)

8 ≤ 40

[Im not sure if this is a solution or and inequality :/ ]

3)  x < 5

--> On the line, draw the number 0, and the number five. 'x < 5' also means 'x is less that five.' So, draw a dot over the line before 5, and make an arrow going to the left of the page,

<-----------------------------------o   5

<---|---|---|---|---|---|---|---|---|---|---|---|---|---|--->

                          0

Hopefully this helps! :)

4 0
3 years ago
Can you guys help me please :(
ale4655 [162]

Answer:

720 m²

Step-by-step explanation:

Area = base × height

= 12 × 6

= 72 mm²

≈ 720 m² (1 mm = 10 m)

5 0
2 years ago
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topjm [15]

Answer:

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

Step-by-step explanation:

By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:

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V_{c} = l\cdot w\cdot h (1)

Wading pool

V_{w} = \left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w (2)

Where:

l – Length of the swimming pool, measured in feet.

h – Depth of the swimming pool, measured in feet.

w – Width of the swimming pool, measured in feet.

V_{c} – Volume of the community swimming pool, measured in cubic feet.

V_{w} – Volume of the wading swimming pool, measured in cubic feet.

The ratio of the volume of the community swimming pool to the volume of the wadling pool is:

\frac{V_{c}}{V_{w}} = \frac{l\cdot w \cdot h}{\left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w} (3)

\frac{V_{c}}{V_{w}} = \frac{1}{\frac{1}{4} }

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Answer:

B. -1/8

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So, each term is multiplied by -1/2 to get the next term in the sequence:

\frac{1}{4}*-\frac{1}{2}=-\frac{1}{8}

3 0
4 years ago
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