Solving systems of equations algebraically.

1 answer:

7 0

Start with x=y+13 then plug it in so you get 4(y+13) + 2y = 10
Then you get 4y + 52 +2y =10
Then you add you similarities to get 6y + 52= 10
Subtract 52 from both sides gets you 6y=-42. Then you divide and you get y=-7.
Then you plug that into your original equation so 4x + 2(-7) = 10
4x + -14 = 10
4x = 24
X= 6
Y= -7

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So, let's make these two values improper fractions so they're easier to work with. $4+\frac{1}{3}=\frac{12}{3}+\frac{1}{3}=\frac{13}{3} 3+\frac{1}{2}=\frac{6}{2}+\frac{1}{2}=\frac{7}{2}$