Answer:
6 hours
Step-by-step explanation:
180 divided by 30 = 6
Answer:The whole numbers are the numbers 0, 1, 2, 3, 4, and so on (the natural numbers and zero). Negative numbers are not considered "whole numbers." All natural numbers are whole numbers, but not all whole numbers are natural numbers since zero is a whole number but not a natural number.
Step-by-step explanation:
Answer:
The liters that the tank will contain at 5:11 PM that day are:
Step-by-step explanation:
Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:
- 19,140 L - 8,097 L = 11,043 L
And the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:
- Outlet flow =
- Outlet flow =
- Outlet flow = 613.5
![\frac{L}{min}](https://tex.z-dn.net/?f=%5Cfrac%7BL%7D%7Bmin%7D)
Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:
- Outlet flow =
- Volume = Outlet flow * time
And replace the values to obtain the new volume pumped:
- Volume = 613.5
* 6 min - Volume = 3681 L.
At last, you must subtract these liters from the last volume identified in the tank:
- New Volume in the tank = 8097 L - 3681 L
- New Volume in the tank = 4416 L
The volume in the tank at 5:11 PM is <u>4416 Liters</u>.
Answer:
11
Step-by-step explanation:
The diagonals of a parallelogram bisect each other. The value of x is the same as the length of the other half of the diagonal:
x = 11
Answer:
A. x = 9
D. x = 0
Step-by-step explanation:
The formula to solve a quadratic equation of the form
is equal to
![x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
in this problem we have
so
![a=6\\b=-54\\c=0](https://tex.z-dn.net/?f=a%3D6%5C%5Cb%3D-54%5C%5Cc%3D0)
substitute in the formula
![x=\frac{-(-54)(+/-)\sqrt{-54^{2}-4(6)(0)}} {2(6)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-54%29%28%2B%2F-%29%5Csqrt%7B-54%5E%7B2%7D-4%286%29%280%29%7D%7D%20%7B2%286%29%7D)
![x=\frac{54(+/-)54} {12}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B54%28%2B%2F-%2954%7D%20%7B12%7D)
therefore
The solutions are x=0 and x=9