The three numbers are 12, 18 and 24
Arithmetic progression
Let the 3 number in arithmetic progression be:
a-d, d, a+d ...
If their sum is 3, then;
a-d+d+a+d = 3
2a + d = 3 ........... 1
If the sum of their squares is 11, then;
(a-d)² + d² + (a+d)² = 11
a²-2ad+d²+d²+a²+2ad+d² 11
2a²+3d² = 11 ....... 2
Solving the equations simultaneously, d = 6 and a = 12
First-term = 12
second term = 18
Thirs term = 24
Hence the three numbers are 12, 18 and 24
Hope this helps you!!!!!! :D
The answer is x-2 plz give brainliest and good luck!
y=4/3-x/6
Step-by-step explanation:
6y/6+x/6=8/6
y+x/6=4/3
-x/6 -x/6
y=4/3-x/6
Step-by-step explanation: The 9 in 857.9 differs from the value of 9 in 798.21 because in 857.9, the 9 is in the tenths place, while in 798.21, it is in the tens place.
